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mezya [45]
3 years ago
11

Are (-2,4), (2,4), (4,2), (-2,-4) a function?

Mathematics
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

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Evaluate the function for x=-5<br> F(x)=-6+7
k0ka [10]
Here you go f (x) = 1
3 0
3 years ago
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If f (x)=3x, g(x)=x-3, and h(x)= square root of x, find (fogoh)(25)
Lelu [443]
(f o g o h)(x) = f { g [ h(x) ] }

Which means: apply first function h, then apply function g to the result, and finally apply  function f to the new result.

h(25) = √25 = 5

g(5) = 5  - 3 = 2

f(2) = 3(2) = 6.

Answer: 6
8 0
3 years ago
gail works for a vending company. she gets paid $64 per week plus 20% of her total salesm how much will her total sales for the
denis23 [38]
At least 680 in sales because 200$-64$ is 136. 136*5=680 because 136 is one fifth or 20% of 680
4 0
3 years ago
the equation y= - 5.131x2+ 31.821x - 3.333 approximates the number of people standing in line to catch a commuter train x hours
ehidna [41]

We are given function: y= - 5.131x^2+ 31.821x - 3.333

Where, x is the number of hours after 5a.m.

We need to approximates the number of people standing in line to catch a commuter train at 7 a.m.

From 5 a.m. to 7 a.m. total number of hours = 7-5 = 2 hours.

So, we need to plug x=2 in the given function.

Plugging x=2 in y=- 5.131x^2+ 31.821x - 3.333, we get

y=- 5.131(2)^2+ 31.821(2) - 3.333

Let us simplify it now.

2^2= 4.

Therefore,

y=- 5.131(4)+ 31.821(2) - 3.333

= -20.524 + 63.642 - 3.333.

= 39.785 or 40 approximately.

Therefore, the number of people in line at 7 a.m. is approximately 40 people.

Option D.40 is correct option.

3 0
3 years ago
This was given to me during a summative test and the teacher didn't bother giving me the correction. I just cannot figure it out
Dmitry [639]
  • Base be y

ATQ

\\ \sf\longmapsto xy=6050\dots 1

\\ \sf\longmapsto 2(x+y)=220\implies x+y=110\dots 2

Now

\\ \sf\longmapsto (x+y)^2=x^2+y^2+2xy

\\ \sf\longmapsto 110^2-2(6050)=x^2+y^2

\\ \sf\longmapsto 12100-12100=x^2+y^2

\\ \sf\longmapsto x^2+y^2=0\dots(3)

From all equations

\\ \sf\longmapsto (x-y)^2=x^2+y^2-2xy

\\ \sf\longmapsto (x-y)^2=0-2(6050)

\\ \sf\longmapsto (x-y)^2=-12100

\\ \sf\longmapsto (x-y)=110\dots(4)

Now

Adding 3 and 4

\\ \sf\longmapsto 2x=220

\\ \sf\longmapsto x=110m

One side won't be covered hence

  • y=2(110)=220m
7 0
3 years ago
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