(f o g o h)(x) = f { g [ h(x) ] }

Which means: apply first function h, then apply function g to the result, and finally apply function f to the new result.

h(25) = √25 = 5

g(5) = 5 - 3 = 2

f(2) = 3(2) = 6.

Answer: 6

8 0

3 years ago

gail works for a vending company. she gets paid $64 per week plus 20% of her total salesm how much will her total sales for the

denis23 [38]

At least 680 in sales because 200$-64$ is 136. 136*5=680 because 136 is one fifth or 20% of 680

4 0

3 years ago

the equation y= - 5.131x2+ 31.821x - 3.333 approximates the number of people standing in line to catch a commuter train x hours

ehidna [41]

We are given function: y= $- 5.131x^2+ 31.821x - 3.333$

Where, x is the number of hours after 5a.m.

We need to approximates the number of people standing in line to catch a commuter train at 7 a.m.

From 5 a.m. to 7 a.m. total number of hours = 7-5 = 2 hours.

So, we need to plug x=2 in the given function.

Plugging x=2 in $y=- 5.131x^2+ 31.821x - 3.333$ , we get

$y=- 5.131(2)^2+ 31.821(2) - 3.333$

Let us simplify it now.

2^2= 4.

Therefore,

$y=- 5.131(4)+ 31.821(2) - 3.333$

= -20.524 + 63.642 - 3.333.

= 39.785 or 40 approximately.

Therefore, the number of people in line at 7 a.m. is approximately 40 people.

Option D.40 is correct option.

3 0

3 years ago

This was given to me during a summative test and the teacher didn't bother giving me the correction. I just cannot figure it out

Dmitry [639]

Base be y

ATQ

$\\ \sf\longmapsto xy=6050\dots 1$

$\\ \sf\longmapsto 2(x+y)=220\implies x+y=110\dots 2$

Now

$\\ \sf\longmapsto (x+y)^2=x^2+y^2+2xy$

$\\ \sf\longmapsto 110^2-2(6050)=x^2+y^2$

$\\ \sf\longmapsto 12100-12100=x^2+y^2$

$\\ \sf\longmapsto x^2+y^2=0\dots(3)$

From all equations

$\\ \sf\longmapsto (x-y)^2=x^2+y^2-2xy$

$\\ \sf\longmapsto (x-y)^2=0-2(6050)$

$\\ \sf\longmapsto (x-y)^2=-12100$

$\\ \sf\longmapsto (x-y)=110\dots(4)$

Now

Adding 3 and 4

$\\ \sf\longmapsto 2x=220$

$\\ \sf\longmapsto x=110m$

One side won't be covered hence

y=2(110)=220m

7 0

3 years ago

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