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Varvara68 [4.7K]
2 years ago
14

If an object has an initial velocity wouldn’t hit the ground first then a other object with no initial velocity

Physics
1 answer:
WARRIOR [948]2 years ago
7 0

The initial velocity given one object will make it hit the ground first.

<h3>What is velocity?</h3>

Velocity is the displacement of a body in a given time interval.

Velocity is a vector quantity since displacement is also a vector quantity.

  • Velocity = Displacement/time

Two objects are released from a certain height above the ground.

One is given an initial velocity while the other had no initial velocity.

The two objects are accelerated to the same extent by gravity.

However, because of the initial downward velocity of the first object, it will hit the ground first.

In conclusion, the initial velocity given one object will make it travel faster than the other object.

Learn more about initial velocity at: brainly.com/question/21010554

#SPJ1

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The family may be addicted to technology by using their cellphones to communicate is still communicating in a way, but it would be better to use social face- to - face interactions.

Explanation:

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Explain, using your own words, how noise cancelling headphones work, (physics)
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They use noise control, creating a wave that negates outside or ambient sound and replaces it with the desired sound that listeners request.

Explanation:

I hope this helped

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3 years ago
Anyone know the answer ?
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Momentum = mass x velocity, so 500kg x 2m/s = 1000 kg m/s
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3 years ago
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A traves de una manguera de 1 in de diámetro fluye gasolina con una velocidad media de 5ft/s ¿cuál es el gasto?
jonny [76]

Answer:

El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.

Explanation:

El gasto es el flujo volumétrico de gasolina (Q), medido en pies cúbicos por segundo, que sale de la manguera. Asumiendo que la velocidad de salida es constante, tenemos que el gasto a través de la manguera es:

Q = \frac{\pi}{4}\cdot D^{2}\cdot v (1)

Donde:

D - Diámetro de la manguera, medido en pies.

v - Velocidad medida de salida, medida en pies por segundo.

Si sabemos que D = \frac{1}{12}\,ft y v = 5\,\frac{ft}{s }, entonces el gasto de gasolina es:

Q = \frac{\pi}{4}\cdot \left(\frac{1}{12}\,ft \right)^{2} \cdot \left(5\,\frac{ft}{s} \right)

Q \approx 0.0273\,\frac{ft^{3}}{s}

El gasto de gasto es de aproximadamente 0.0273 pies cúbicos por segundo.

6 0
3 years ago
A 53.0-kg skater is traveling due east at a speed of 2.90 m/s. A 72.0-kg skater is moving due south at a speed of 6.20 m/s. They
soldier1979 [14.2K]

Answer:

a.\thta=71^{\circ}

b.v_f=3.78 m/s

Explanation:

We are given that

m_1=53 kg

v_1=2.9 m/s

m_2= 72 kg

v_2=6.2 m/s

a.We have to find the angle

\theta=tan^{-1}{\frac{m_2v_2}{m_1v_1}=\frac{72(6.2)}{53(2.9)}=71^{\circ}

\theta=71^{\circ}

b. We have to find the speed v_f

According to law of conservation of momentum

m_1v_1=(m_1+m_2)v_fcos\theta

53(2.9)=(53+72)v_fcos 71^{\circ}=40.7 v_f

v_f=\frac{153.7}{40.7}=3.78 m/s

3 0
3 years ago
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