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Varvara68 [4.7K]
2 years ago
14

If an object has an initial velocity wouldn’t hit the ground first then a other object with no initial velocity

Physics
1 answer:
WARRIOR [948]2 years ago
7 0

The initial velocity given one object will make it hit the ground first.

<h3>What is velocity?</h3>

Velocity is the displacement of a body in a given time interval.

Velocity is a vector quantity since displacement is also a vector quantity.

  • Velocity = Displacement/time

Two objects are released from a certain height above the ground.

One is given an initial velocity while the other had no initial velocity.

The two objects are accelerated to the same extent by gravity.

However, because of the initial downward velocity of the first object, it will hit the ground first.

In conclusion, the initial velocity given one object will make it travel faster than the other object.

Learn more about initial velocity at: brainly.com/question/21010554

#SPJ1

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A motorboat approaches you head-on and sounds one short blast. how do you signal that you agree to let it pass on your port (lef
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Why is the efficiency of a machine always less than 100%?
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Answer:The percentage of the work input that becomes work output is the efficiency of a machine. Because there is always some friction, the efficiency of any machine is always less than 100 percent.

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A maintenance worker wants to torque an engine bolt to 65.0 N m. If the torque wrench is 35cm in length, what is force applied t
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Force = 186 N

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Torque = \vec{r} \times \vec{F}

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The easiest way of computing the force is by setting the origin of the coordinate system to the lowest point of the torque wrench.  By doing this we have that r (the magnitud of the position vector) is 35cm.

Before computing the force we need to set all our values to the international system of units (SI). The torque is already in SI. The one missing is the length of the torque wrench (it is in centimeters and we need it in meters). So :

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Now using the torque formula:

Torque = \vec{r} \times \vec{F}

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Where \theta is the smaller angle between the force and the position vector. Because the force is applied perpendiculary to the position vector  \theta = 90°, thus :

Torque = rFsin(\theta)}

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F = \dfrac{65N m} {(0.35m)sin(90°)}

F = \dfrac{65N m} {(0.35m)sin(90°)}

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4 years ago
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