Answer:
1.) Current = 213.33A
2.) Potential difference = 3200 V
Explanation:
Given that
Number of electrons n = 4 x 10^21 electrons
Resistance R = 15 ohm
Time t = 3 s
From the definition of current ;
Current is the rate of flow of changes. That is,
Current I = Q/t
Where
Q = 4 × 10^21 × 1.6 × 10^-19
Q = 460C
Current I = 460/3
Current I = 213.33 A
Using Ohms law which state that
V = IR
Substitute the resistance R and current I into the formula above
Potential difference V = 213.3 × 15
Potential difference V = 3200 V
Answer:
28.3 m/s
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 30°
Maximum height (H) = 10 m
Acceleration due to gravity (g) = 10 m/s²
Initial velocity (u) =?
Thus, we can obtain the minimum velocity cannon ball by using the following formula:
H = u²Sine² θ / 2g
10 = u² × (Sine 30)² / 2× 10
10 = u² × (0.5)² / 20
10 = u² × 0.25 / 20
10 = u² × 0.0125
Divide both side by 0.0125
u² = 10/ 0.0125
u² = 800
Take the square root of both side
u = √800
u = 28.3 m/s
Therefore, the minimum speed of the cannon ball is 28.3 m/s
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True, air moves from high to low pressure wanting to expand as much as possible.
