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Mumz [18]
3 years ago
8

Which lobes of the brain receive the input that enables you to feel someone scratching your back? (2 points)

Physics
1 answer:
andrew-mc [135]3 years ago
3 0

Answer: Parietal

Explanation: The parietal lobe is where the primary somatosensory cortex is located. This cortex is where all tactile stimulation is processed in the brain and allows to you detect/feel someone scratching your back.

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What is the force on an object with a mass of 25 kg and an acceleration of 5 m/s/s? 1 point
Oduvanchick [21]

Answer:125N

Explanation:

Mass =25kg

Acceleration =5m/s/s

Force=mass x acceleration

Force=25 x 5

Force=125N

7 0
3 years ago
The graph indicates Linda’s walk.
Sedaia [141]
I think the right answer is the first one. If she stops moving her Position does not change any more-and the Graph Shows that after 6 seconds she stays at the Position of 5 m. If she Went Back to the start point the Graph would have Developed Back to 0m(decreased).
3 0
3 years ago
Read 2 more answers
In a local park, a pine cone falls off a tree branch (starting at rest) and falls to the ground. We will model the pine cone hit
Liono4ka [1.6K]

Answer:

1)) ΔU = -8.96 J, 2)    k = 8.18 10⁴ N / m, 3)  v = 8.47 m / s

Explanation:

For this exercise we will use conservation of energy.

Starting point. Point where the pineapple comes out

          Em₀ = U = m g h

where the reference frame is placed on the ground

Final point. Point where pineapple stops

          Em_f = K_e + U = ½ k y² + m g y

1) the change in gravitational potential energy is

           ΔU = U_f - U₀

           ΔU = m g y - m g h

           ΔU = mg (y-h)

         

let's calculate

            ΔU = 0.116 9.8 (0.0148 - 7.9)

            ΔU = -8.96 J

The negative sign indicates that the energy decreases

2) let's use energy conservation

             Em₀ = Em_f

             mg h = ½ k y² + mg y

             k = mg (h-y) \frac{2}{y^2}

             

let's calculate

             k = 0.116 9.8 (7.9 - 0.0148)    \frac{2}{0.0148^2}  

             k = 8.18 10⁴ N / m

3) we use the same starting point and as the end point we use this height (y₂ = 4.24 m)

             Em_{f2} = K + U = ½ m v² + mg y₂

             

energy is conserved

             Em₀ = Em_{f2}

              mgh = ½ m v² + m g y₂

              v =\sqrt{  2g(h-y_2)}

let's calculate

              v = \sqrt{ 2 \ 9.8 \ (7.9-4.24)}

              v = 8.47 m / s

6 0
3 years ago
A fence post is 52.0 m from where you are standing, in a direction 37.0° north of east. A second fence post is due south from yo
galina1969 [7]

Answer:

22.5 [m] is the distance from the person to the second post.

Explanation:

We can solve this problem graphically, first place the position of the person at the origin of x-y coordinates.

Then we locate the first post (1), tracing a line (or vector) with a length of 52 [m] from the origin of coordinates and with an angle of 37 ° north of East.

And for finding the distance from the second post (2) with respect to the person, we have to draw a line that has a length of 68 [m] and this line must be crossed with the y-axis and in the negative direction, in this way we can find the distance from the post with respect to the person.

Note: we can use set square and protractor to solve this problem

In the attached image we can find the graphic solution.

By this method of construction we can find the distance of post number 2 from the person and this is 22.55 [m] to the South

8 0
3 years ago
28. Cooking requires continuous addition of energy to the chemical reactions that are taking place. The chemical reactions invol
Goshia [24]
Endothermic I believe is the answer
4 0
3 years ago
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