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Mumz [18]
3 years ago
8

Which lobes of the brain receive the input that enables you to feel someone scratching your back? (2 points)

Physics
1 answer:
andrew-mc [135]3 years ago
3 0

Answer: Parietal

Explanation: The parietal lobe is where the primary somatosensory cortex is located. This cortex is where all tactile stimulation is processed in the brain and allows to you detect/feel someone scratching your back.

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What is work done in physics and how can it be calculated
shusha [124]
Work is done when a force is applied to an object moves that object. the work is calculated by multiplying the force by the amount of movement of an object
8 0
3 years ago
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One mole of titanium contains how many atoms?
Vladimir [108]

Answer:

\boxed {\boxed {\sf D. \ 6.02*10^{23} \ atoms}}

Explanation:

One mole of a substance contains the same amount of representative particles. These particles can be atoms, molecules, ions, or formula units. In this case, the particles are atoms of titanium.

Regardless of the particles, there will always be <u>6.02*10²³</u> (also known as Avogadro's Number) particles in one mole of a substance.

Therefore, the best answer for 1 mole of titanium is D. 6.02*10²³ atoms.

3 0
3 years ago
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Can I get a direct answer please??
OleMash [197]
Get a direct answer of what???
7 0
3 years ago
A diffraction grating has 500 slits/mm. What is the longest wavelength of light for which there will be a third-order maximum?
Alexxandr [17]

Answer:

The longest wavelength of light  is 666.7 nm

Explanation:

The general form of the grating equation is

mλ = d(sinθi + sinθr)

where;

m is third-order maximum = 3

λ is the wavelength,

d is the slit spacing (m/slit)

θi  is the incident angle

θr is the diffracted angle

Note: at longest wavelength, sinθi + sinθr = 1

λ = d/m

d = 1/500 slits/mm

λ = 1 mm/(500 *3) = 1mm/1500 = 666.7 X 10⁻⁶ mm = 666.7 nm

Therefore, the longest wavelength of light  is 666.7 nm

8 0
3 years ago
It has been suggested that rotating cylinders several miles in length and several miles in diameter be placed in space and used
stepladder [879]

Answer:

the required revolution per hour is 28.6849

Explanation:

Given the data in the question;

we know that the expression for the linear acceleration in terms of angular velocity is;

a_{c} = rω²

ω² = a_{c} / r

ω = √( a_{c} / r )

where r is the radius of the cylinder

ω is the angular velocity

given that; the centripetal acceleration equal to the acceleration of gravity a a_{c}  = g = 9.8 m/s²

so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m

Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m

so we substitute

ω = √( 9.8 m/s² / 3909.87 m )

ω = √0.002506477 s²  

ω = 0.0500647 ≈ 0.05 rad/s  

we know that; 1 rad/s = 9.5493 revolution per minute

ω = 0.05 × 9.5493 RPM

ω = 0.478082 RPM  

1 rpm = 60 rph  

so  

ω = 0.478082 × 60

ω = 28.6849  revolutions per hour  

Therefore, the required revolution per hour is 28.6849

7 0
3 years ago
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