Answer:125N
Explanation:
Mass =25kg
Acceleration =5m/s/s
Force=mass x acceleration
Force=25 x 5
Force=125N
I think the right answer is the first one. If she stops moving her Position does not change any more-and the Graph Shows that after 6 seconds she stays at the Position of 5 m. If she Went Back to the start point the Graph would have Developed Back to 0m(decreased).
Answer:
1)) ΔU = -8.96 J, 2) k = 8.18 10⁴ N / m, 3) v = 8.47 m / s
Explanation:
For this exercise we will use conservation of energy.
Starting point. Point where the pineapple comes out
Em₀ = U = m g h
where the reference frame is placed on the ground
Final point. Point where pineapple stops
Em_f = K_e + U = ½ k y² + m g y
1) the change in gravitational potential energy is
ΔU = U_f - U₀
ΔU = m g y - m g h
ΔU = mg (y-h)
let's calculate
ΔU = 0.116 9.8 (0.0148 - 7.9)
ΔU = -8.96 J
The negative sign indicates that the energy decreases
2) let's use energy conservation
Em₀ = Em_f
mg h = ½ k y² + mg y
k = mg (h-y)
let's calculate
k = 0.116 9.8 (7.9 - 0.0148)
k = 8.18 10⁴ N / m
3) we use the same starting point and as the end point we use this height (y₂ = 4.24 m)
Em_{f2} = K + U = ½ m v² + mg y₂
energy is conserved
Em₀ = Em_{f2}
mgh = ½ m v² + m g y₂
v =
let's calculate
v =
v = 8.47 m / s
Answer:
22.5 [m] is the distance from the person to the second post.
Explanation:
We can solve this problem graphically, first place the position of the person at the origin of x-y coordinates.
Then we locate the first post (1), tracing a line (or vector) with a length of 52 [m] from the origin of coordinates and with an angle of 37 ° north of East.
And for finding the distance from the second post (2) with respect to the person, we have to draw a line that has a length of 68 [m] and this line must be crossed with the y-axis and in the negative direction, in this way we can find the distance from the post with respect to the person.
Note: we can use set square and protractor to solve this problem
In the attached image we can find the graphic solution.
By this method of construction we can find the distance of post number 2 from the person and this is 22.55 [m] to the South