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3 years ago

7

Benny gets a job at a law firm with a salary of $70,000 per year. After the first year, his salary increases to $73,000. Over th

e next five years, he gets an increase of $3,000 every year.

1 answer:

KonstantinChe [14]3 years ago

5 0

The answer is 88,000

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An acute triangle had two sides measuring 8cm and 10 cm what is the best representation of the possible range of values for tge

katrin2010 [14]

The third side must be >2 and < 18

To test if a triangle is acute, right or obtuse:
1) Square all 3 sides
2) Sum the squares of the 2 shortest sides
3) Compare this sum to side 3 squared
if sum > side 3 squared it is an acute triangle
if sum = side 3 squared it is a right triangle
if sum < side 3 squared it is an obtuse triangle

The shortest side 2 can be is "less than 2" so we'll say it is 2.00000001
three sides squared =
<span> <span> <span> 4.00000004 </span> </span> </span>
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Summing the 2 shortest sides 4.00000004 + 64 = <span>68.00000004
</span><span>68.00000004 is less than 100 so it is an obtuse triangle no matter how long the third side is.

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3 years ago

Let f(x) = 8x3 + 16x2 − 15 and g(x) = 2x + 1. Find f of x over g of x.

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Answer:

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3 years ago

Ms. Wall will roll a single number cubes. What is the probability that she will roll an even number?

Arturiano [62]

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3 years ago

A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

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3 years ago

Ummm help please becuase i don't know the answer so plese help

Bezzdna [24]

It goes 2, 4, 10, 20 euros
(1,2)
(2,4)
(5,10)
(10,20)

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3 years ago

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