Basically add up the given side lengths and subtract that from 180 for the triangles
I'm pretty sure the answer is no. A function looks like this: f(x) = mx + c. Let's add another function, f(y) = ny + d. If the x-intercept is the same, we can subtract c and d from their respective equations. f(x) = mx, f(y) = ny. If the domains are the same, then x and y can have the same value, so we divide it out. f(x) = m, f(y) = n. Finally, if the ranges are the same, the value of f(x) = f(y). So by the substitution property, m=n. Since all the variables equal each other, both functions are equal to f(x) = mx+c! Therefore, they can only be the same function.
Answer: No
Answer:
t=0 and t=5
Step-by-step explanation:
5t = t^2
Subtract 5t from each side
5t-5t = t^2 -5t
0= t^2 -5t
Factor out a t
0= t(t-5)
Using the zero product property
t=0 and t-5 =0
t=0 and t-5+5=0+5
t=0 and t=5
#1) 5/20
#2) 7/300
#3) 3/50
#4) 5/20
Explanation
For #1:
There are 15 even numbers out of 30. Since it is replaced before drawing the second ball, there will be 15 odd numbers out of 30. This gives us
15/30(15/30) = 225/900 = 5/20.
For #2:
There is 1 7 out of 30; then there are 14 numbers greater than 16 out of 30:
1/30(14/30) = 14/900 = 7/300
For #3:
There are 6 multiples of 5 out of 30; then there are 9 prime numbers out of 30:
6/30(9/30) = 54/900 = 3/50
For #4:
There are 15 even numbers out of 30; then there are still 15 even numbers out of 30:
15/30(15/30) = 225/900 = 5/20
