Answer:
6844.5 m/s.
Explanation:
To get the speed of the satellite, the centripetal force on it must be enough to change its direction. This therefore means that the centripetal force must be equal to the gravitational force.
Formula for centripetal force is;
F_c = mv²/r
Formula for gravitational force is:
F_g = GmM/r²
Thus;
mv²/r = GmM/r²
m is the mass of the satellite and M is mass of the earth.
Making v the subject, we have;
v = √(GM/r)
We are given;
G = 6.67 × 10^(-11) m/kg²
M = 5.97 × 10^(24) kg
r = 8500 km = 8500000
Thus;
v = √((6.67 × 10^(-11) × (5.97 × 10^(24)) /8500000) = 6844.5 m/s.
I want to improve my speed
Answer:
The magnetic flux through the two cubes is zero in both cases
Explanation:
To answer this question, we have to think about the nature of magnetic fields.
In fact, we know that magnetic sources always exist only as magnetic dipoles: this means that a magnet always has a north pole (from which the magnetic field lines go away) and a south pole (into which the magnetic field lines return). There exist no magnetic monopoles: even when we cut a magnet in a half, we end up having two magnets, each of them having its own north pole and south pole.
A direct consequence of this fact is that if we take a closed surface, such as a cube surrounding the magnet, the magnetic flux through the cube is always zero. This is because all the field lines going out the surface of the cube always return inside the cube on another point. Since the magnetic flux basically represents the number of field lines passing through the surface of the cube, this means that the net positive magnetic flux (lines going out of the cube) is equal to the net negative magnetic flux (lines going into the cube).
As a result, the magnetic flux is zero for both the smaller cube and the larger cube.
Answer:
1 m/s
Explanation:
Po = Pf
(0.050kg)(9 m/s) + (0.030kg)(v2) = (0.05kg + 0.030)(6 m/s)
0.45 kgm/s + (0.030kg)(v2) = 0.48 kgm/s
(0.030kg)(v2) = 0.03 kgm/s
v2 = 1 m/s
Answer:
A) 0.120
B) 1.6s
C) 0.625 Hz
Explanation:
Here, X = 0.120 m
x = 0.120 m after t = 0.800 s
A- Amplitude = max displacement from equillibrium position = 0.120 m
B- Period = 2 * 0.800 = 1.6 s
C- Frequency = 1/peroid = 1/1.6
f = 0.625 Hz
