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Andreyy89
3 years ago
15

What evidence shows that the burning of methane is a chemical reaction?

Physics
2 answers:
ratelena [41]3 years ago
8 0

Answer:

ok ko lets fight to the end you are my best friend lets make it up

Explanation:

sleet_krkn [62]3 years ago
5 0
<span>The burning of methane is a chemical reaction, There is a</span> change in temperature and the production of gases is the evidence. This <span>chemical change results in the formation of 1 or more new substances and a new compound is create.  </span>Methane<span> burns with a smokey flame that forms carbon dioxide and water, which makes it a </span>chemical reaction.
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An acorn falls from an oak tree. You note that it
Vaselesa [24]

Answer:9.8 m/s²

Explanation:

It was going at 9.8m/s² as this is the acceleration of an object due to gravity

when an object falls it accelerates at a consant and uniform speed which is 9.8m/s²

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3 years ago
A wheelbarrow is a complex machine that combines which simply marchines?
koban [17]
It's most likely the combination of a bucket and the wheel. 
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3 years ago
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Y=-3x +4 find the domain Nd range
aksik [14]
Is 3678.555667775 correct
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2 years ago
An astronaut has a mass of 100 kg and has a weight and if 370 N on Mars. What is the gravitational strength on Mars?
Reika [66]

Answer:

3.7 N/kg

Explanation:

The gravitational strength refers to the amount of gravity acting per unit mass. Hence in this case,

Gravitational Strength = Weight / Mass

= 370 / 100

= <u>3</u><u>.</u><u>7</u><u>N</u><u>/</u><u>k</u><u>g</u>

4 0
3 years ago
A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is find the speed of the block as it
SashulF [63]

Answer:

2.4\sqrt{L} where L is the length of the ramp

Explanation:

Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.

The parallel component would have a magnitude of

gsin\theta = 9.81 sin17^o = 2.87 m/s^2

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

v^2 - v_0^2 = 2a\Delta s

where v m/s is the final velocity, v_0 = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and \Delta s = L is the distance traveled:

v^2 - 0 = 2*2.87*L

v = \sqrt{5.74L} = 2.4\sqrt{L}

6 0
3 years ago
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