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3 years ago

Two identical soccer balls are rolled toward each other. What will be true after they collide head-on? (2 points)

1 answer:

8 0

well it depends on how much force was added but if they both have the same amount of force and they were rolled at the same time either they will bounce backwards or roll backwards not thats your question will they roll backwards are bounce backwards?

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During a physical science lab investigating chemical reactions, several students placed a 30g antacid tablet in a 30g zip-lock b

ICE Princess25 [194]

30 Grams would be your answer (I took the test and got it right)

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2 years ago

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Which statement best describes how the distance from a large river affects an area’s climate in the summer?

Montano1993 [528]

Answer:

Regions near rivers have water surfaces that rapidly change in temperature from cold to hot.

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2 years ago

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What is the acceleration of a rocket that speeds up from 50 m/s to 1000 m/s in 3 seconds?

Zepler [3.9K]

Answer:

= 316.67 m/s^2

Explanation:

Acceleration formula =

A = $\frac{V_{f} - V_{i} }{t}$

$A = \frac{1000 - 50}{3}$

= $\frac{950}{3}$

= 316.67 m/s^2

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2 years ago

A 16000 kg railroad car travels along on a level frictionless track with a constant speed of 23.0 m/s. A 5400 kg additional load

Alisiya [41]

Answer:

The speed of the car when load is dropped in it is 17.19 m/s.

Explanation:

It is given that,

Mass of the railroad car, m₁ = 16000 kg

Speed of the railroad car, v₁ = 23 m/s

Mass of additional load, m₂ = 5400 kg

The additional load is dropped onto the car. Let v will be its speed. On applying the conservation of momentum as :

$m_1v_1=(m_1+m_2)v$

$v=\dfrac{m_1v_1}{m_1+m_2}$

$v=\dfrac{16000\ kg\times 23\ m/s}{(16000+5400)\ kg}$

v = 17.19 m/s

So, the speed of the car when load is dropped in it is 17.19 m/s. Hence, this is the required solution.

6 0

2 years ago

What does the rotational speed of the ring module have to be so that an astronaut standing on the outer rim of the ring module f

Usimov [2.4K]

Complete question:

In the movie The Martian, astronauts travel to Mars in a spaceship called Hermes. This ship has a ring module that rotates around the ship to create “artificial gravity” within the module. Astronauts standing inside the ring module on the outer rim feel like they are standing on the surface of the Earth. (The trailer for this movie shows Hermes at t=2:19 and demonstrates the “artificial gravity” concept between t= 2:19 and t=2:24.)

Analyzing a still frame from the trailer and using the height of the actress to set the scale, you determine that the distance from the center of the ship to the outer rim of the ring module is 11.60 m

What does the rotational speed of the ring module have to be so that an astronaut standing on the outer rim of the ring module feels like they are standing on the surface of the Earth?

Answer:

The rotational speed of the ring module have to be 0.92 rad/s

Explanation:

Given;

the distance from the center of the ship to the outer rim of the ring module r, = 11.60 m

When the astronaut standing on the outer rim of the ring module feels like they are standing on the surface of the Earth, then their centripetal acceleration will be equal to acceleration due to gravity of Earth.

Centripetal acceleration, a = g = 9.8 m/s²

Centripetal acceleration, a = v²/r

But v = ωr

a = g = ω²r

$\omega = \sqrt{\frac{g}{r}} = \sqrt{\frac{9.8}{11.6} } = 0.92 \ rad/s$

Therefore, the rotational speed of the ring module have to be 0.92 rad/s

3 0

3 years ago