Answer:
A. 0.806 kN
B. 0.303 kN
Explanation:
<h3>A.</h3>
The kinetic energy of the ball is ...
KE = 1/2mv² = 1/2(0.206 kg)(18 m/s)² = 33.372 J
The work required to reduce this to zero over a distance of 4.14 cm is ...
W = Fd
F = W/d = (33.372 J)/(0.0414 m) = 0.806 kN
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<h3>B.</h3>
When the distance is 11 cm, the force is ...
F = (33.372 J)/(0.11 m) = 0.303 kN
Magma, first, outer layer, inner layer
March has 31 days.
3 Marches have 93 days.
Each day has 86,400 seconds.
(93 days) x (86,400 sec/day) = 8,035,200 sec.
From the graph given, the y-axis represents the potential energy while the x axis is represents the displacement. To calculate the potential difference, I think the values from point two to point one should be only subtracted.
Potential difference = 200 - 100 = 100 V/m
Answer:
10cm^3
Explanation:
Given data
Mass of steel = 80grams
density of steel= 8 g/cm^3
We know that the formula for density is given as
density= mass/volume
make volume subject of formula
volume= mass/density
volume=80/8
volume= 10cm^3
Hence, the volume 10cm^3