Yall is this right

Pleaseeeeeee answer :3!

Ludmilka [50]

Work = (force) x (distance)

Work = (21 Newtons) x (9 meters) = 189 Joules

Power = (work done) / (time to do the work)

Power = (189 Joules) / (3 sec)

Power = (63 watts/sec)

Power = 63 watts (D)

3 0

2 years ago

A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000

allochka39001 [22]

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

Mass of the car, m = 1700 kg
Velocity of the car, v = 21 m/s
Time of motion, t = 10 s
Additional energy provided by the engine, E₁ = 22,000 J
Energy used in overcoming friction, E₂ = 3,666.67 J

The change in the energy applied to the car is calculated as;

$\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J$

The final speed of the car is calculated as follows;

$\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s$

Thus, the final speed of the car at the given conditions is 30.1 m/s.

Learn more about change in kinetic energy here: brainly.com/question/6480366

4 0

2 years ago

Is it possible to create a visual model (stop motion) of a wave motion using the differential equation for simple harmonic oscil

Alexeev081 [22]

Answer:

Yes.

Explanation:

A particular solution for the 1D wave equation has the form

$\Psi(x,t) \ = \ A \ sin ( \ k x \ + \omega t \ + \phi \ )$

where A its the amplitude, k the wavenumber, ω the angular frequency and φ the phase angle.

Now, for any given position $x_0$ , we can use:

$\phi_0 \ = \ \phi \ + \ k x_0$

so, the equation its:

$\Psi(x_0,t) \ = \ A \ sin ( \omega t \ + \ \phi_0 )$ .

This is the equation for a simple harmonic oscillation!

So, for any given point, we can use a simple harmonic oscillation as visual model. Now, when we move a $\delta$ distance from the original position, we got:

$x_1 = x_0 + \delta$

and

$\phi_1 = \phi \ + k x_1$

now, this its

$\phi_1 = \phi \ + k ( x_0 + \delta)$

$\phi_1 = \phi \ + k x_0 + k \delta$

$\phi_1 = \phi_0 + k \delta$

So, there its a phase angle difference of $k \delta$ . We can model this simply by starting the simple harmonic oscillation with a different phase angle.

8 0

3 years ago

What is the energy equivalent of an object with a mass of 1. 05 g? 3. 15 Ă— 105 J 3. 15 Ă— 108 J 9. 45 Ă— 1013 J 9. 45 Ă— 1016 J

Molodets [167]

Considering the equivalence between mass and energy given by the expression of Einstein's theory of relativity, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

The equivalence between mass and energy is given by the expression of Einstein's theory of relativity, where the energy of a body at rest (E) is equal to its mass (m) multiplied by the speed of light (c) squared:

E=m×c²

This indicates that an increase or decrease in energy in a system correspondingly increases or decreases its mass, and an increase or decrease in mass corresponds to an increase or decrease in energy.

In other words, a change in the amount of energy E, of an object is directly proportional to a change in its mass m.

In this case, you know:

m=1.05 kg
c= 3×10⁸ m/s

Replacing:

E= 1.05 kg× (3×10⁸ m/s)²

Solving:

E= 9.45×10¹⁶ J

Finally, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

Learn more:

brainly.com/question/9477556

5 0

2 years ago

A Ferris wheel at a carnival has a diameter of 58 feet. Suppose a passenger is traveling at 9 miles per hour. (A useful fact: .)

Anastasy [175]

Answer:

a) 27.2 rad/min

b) 260 rev/h

Explanation:

The passenger is traveling at 9 mph, this is the tangential speed.

The relation between tangential speed and angular speed is:

v = r * w

Where

v: tangential speed

r: radius

w: angular speed

Also, the radius is

r = d/2

d is the diameter

Therefore:

v = (d * w)/2

Rearranging:

w = 2*v/d

w = (2*9 mile/h)/(58 feet)

We need to convert the feet to miles

w = (2*9 mile/h)/(0.011 miles) = 1636 rad/h

We divide this by 60 to get it in radians per minute

w = 1636/60 = 27.2 rad/min

Now the angular speed is in radians, to get revolutions we have to divide by 2π

n = v/(π*d)

n = (9 mile/h)/(π*0.011 mile) = 260 rev/h

7 0

3 years ago