What is the approximate wavelength of a light whose second-order dark band forms a diffraction angle of 15.0° when it passes thr
2 answers:
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PART a)
By energy conservation we can say
divide whole equation by mass "m" and plug in all given data
so gymnast will reach the floor with speed 5.21 m/s
PART b)
Now the gymnast bend her knees by 0.1 m and comes to rest
so here we will have
now the force on the gymnast will be
so during landing the force will be 6798.5 N
Answer:
a) p = 95.66 cm, b) p = 93.13 cm
Explanation:
For this problem we use the constructor equation
where f is the focal length, p and q are the distances to the object and the image, respectively
the power of the lens is
P = 1 / f
f = 1 / P
f = 1 / 2.25
f = 0.4444 m
the distance to the object is
the distance to the image is
q = 85 -2
q = 83 cm
we must have all the magnitudes in the same units
f = 0.4444 m = 44.44 cm
we calculate
1 / p = 0.010454
p = 95.66 cm
b) if they were contact lenses
q = 85 cm
1 / p = 0.107375
p = 93.13 cm
Answer:
Explanation:
From the question we are told that:
Mass
Radius
Generally the equation for inertia is mathematically given by