What is 5 1/4% as a fraction?

Julie made identical necklaces out of shell she collected at the beach all together she we use 10 Brown shells 15 black shells a

Lelu [443]

Answer:

Therefore the number of brown shells in each necklace was = 2 brown shells.

Step-by-step explanation:

If Julie made identical necklaces then we can say that number of each different colored shells were equally distributed among the necklaces.

So we can say that to find the number of necklaces we have to find the GCD (greatest common denominator) of the different colored shells.

Therefore the GCD of 10, 15 and 20 is 5.

Therefore Julia made 5 necklaces.

Therefore the number of brown shells in each necklace was = $\frac{10}{5}$ = 2 shells.

4 0

4 years ago

A man on the fifth floor of a building shouts down to a person on the street. If the angle of elevation from the street to the m

AleksandrR [38]

Answer: 57 ft

Step-by-step explanation: Because drawing it up, we can make a right angled triangle with the right angle between the height of the man in the building and the distance out from the building of the man in the street, and the 35 degrees between the line connecting the man in the street with the man in the building, and the line out from the building of the man in the street. Then, tan of the 35 degree angle is = to opposite (40ft)/adjacent (to solve for). By cross multiplication, the A or adjacent (dist out from the building) = 40/0.7 (0.7 = tan of 35 degrees) so the answer is 57 ft.

3 0

3 years ago

Read 2 more answers

x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco

igomit [66]

Answer:

$x=-cos(t)+2sin(t)$

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

$a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0$

Will have a characteristic equation of the form:

$a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0$

Where solutions $r_1,r_2...,r_n$ are the roots from which the general solution can be found.

For real roots the solution is given by:

$y(t)=c_1e^{r_1t} +c_2e^{r_2t}$

For real repeated roots the solution is given by:

$y(t)=c_1e^{rt} +c_2te^{rt}$

For complex roots the solution is given by:

$y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)$

Where:

$r_1_,_2=\lambda \pm \mu i$

Let's find the solution for $x''+x=0$ using the previous information:

The characteristic equation is:

$r^{2} +1=0$

So, the roots are given by:

$r_1_,_2=0\pm \sqrt{-1} =\pm i$

Therefore, the solution is:

$x(t)=c_1cos(t)+c_2sin(t)$

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of $x(t)$ in order to find the constants $c_1$ and $c_2$ :

$x'(t)=-c_1sin(t)+c_2cos(t)$

Evaluating the initial conditions:

$x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1$

And

$x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2$

Now we have found the value of the constants, the solution of the second-order IVP is:

$x=-cos(t)+2sin(t)$

3 0

3 years ago

Give me some tips for the Shsat that is tomorrow.

Aliun [14]

Answer:

1. Sleep well

2. Eat a proper meal to increase your energy

3. Do the ones you are good at first. Skip the harder questions

4. There are 2 parts. One is ELA while the other is math. Do the one that you are good at first so you wouldn't be annoyed.

5. When you are finished filling out the test slip double-check your work that way you could see which one you got wrong.

6. Have faith in yourself. :)

Step-by-step explanation:

8 0

2 years ago

Mr. Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, then how much is his overall budg

Fynjy0 [20]

Answer:

5000 dollars

Step-by-step explanation:

Let his budget be x

16% of x is 800 dollars

.16 * x = 800

Divide each side by .16

.16x/.16 = 800/.16

x=5000

His budget is 5000 dollars

6 0

2 years ago