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Gre4nikov [31]
2 years ago
9

What is the forward rate with continuous compounding for a three-month period starting in one year?

Chemistry
1 answer:
Tamiku [17]2 years ago
5 0

Answer:8.7%

Explanation:

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Protons are positively charged and repel other protons. Which other particle is found in the nucleus and separates protons so th
Leto [7]
Neutrons which doesn't have any charge
6 0
3 years ago
Read 2 more answers
What mass (in grams) of silver contains the same number of atoms as 5.59 grams of sulfur?
Amanda [17]

Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

7 0
3 years ago
Which of these is a mixture?Oxygen, air, sugar or common salt
Westkost [7]
Air is a mixture of several gasses
3 0
4 years ago
A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of water is 4.18 J•g^-1•C^-1. By how much will it’s temp
MrMuchimi

Answer: The temperature rise is 0.53^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g   (1kg=1000g)

c = heat capacity of water = 4.18J/g^0C

Initial temperature  = T_i

Final temperature = T_f  

Change in temperature ,\Delta T=T_f-T_i=?

Putting in the values, we get:

5280J=2400g\times 4.18J/g^0C\times \Delta T

\Delta T=0.53^0C

Thus the temperature rise is 0.53^0C

0 0
4 years ago
A 300 L sample of hydrogen was compressed to a volume of 200 L at STP. If the initial temperature is 35.0 °C,
a_sh-v [17]

Answer:

76.210kPa

Explanation:

\frac{p1v1}{t1}  =  \frac{p2v2}{t2}  \\ p1 =  \frac{p2v2t1}{v1t1} \\ p1 =  \frac{101.325 \times 200 \times 308}{300 \times 273} \\ p1 = 76.210kpa

6 0
3 years ago
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