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Gre4nikov [31]
2 years ago
9

What is the forward rate with continuous compounding for a three-month period starting in one year?

Chemistry
1 answer:
Tamiku [17]2 years ago
5 0

Answer:8.7%

Explanation:

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Where are the transition metals on the periodic table?
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D. In columns 3-12 in the centre of the table
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2 years ago
What is the range of 14 and 25
Alexxandr [17]
Range means the difference between the highest and lowest number. So subtract 25 - 14 which gives you 11.
6 0
3 years ago
Read 2 more answers
Please help me for question 1 and 2
likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
3 years ago
A flask contains 0.83mol of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is th
Angelina_Jolie [31]

Answer: 5.66 dm3

Explanation:

Given that:

Volume of neon gas = ?

Temperature T = 35°C

Convert Celsius to Kelvin

(35°C + 273 = 308K)

Pressure P = 0.37 atm

Number of moles N = 0.83 moles

Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

0.37atm x V = 0.83 moles x 0.0082 atm dm3 K-1 mol-1 x 308K

0.37 atm x V = 2.096 atm dm3

V = (2.096 atm dm3 / 0.37atm)

V = 5.66 dm3

Thus, the volume of the neon gas is 5.66 dm3

5 0
3 years ago
HELLLLLLPPPPPP!!!
poizon [28]
Barium Chloride
Aluminum Iodide
Lithium Phosphide
Sodium Nitride
Potassium Sulfide
Aluminum Oxide
Sodium Oxide
Rubidium Bromide
Calcium Phosphide

hope this helps for the names
4 0
2 years ago
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