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evablogger [386]
2 years ago
7

Classify each of the changes as a physical change or a chemical change.

Chemistry
1 answer:
Mekhanik [1.2K]2 years ago
6 0

The physical changes are:

  • condensation of water vapors
  • carving wax
  • slicing a banana tearing
  • aluminum foil

The chemical changes are:

  • bleaching hair
  • silver tarnishing,
  • frying an egg, and
  • burning paper

<h3>What are physical and chemical changes?</h3>

Physical changes are changes which occur in a substance which may alter the physical properties of the substance but does not affect the chemical properties of the substance. Physical changes are easily reversible

In physical changes, no new substances are formed. Example of a physical change is the melting of ice or candle wax.

Chemical changes are changes which alter the chemical properties of a substance and in which new substances are formed. Example of chemical changes are; the rusting of iron, bleaching hair silver tarnishing, frying an egg, and burning paper.

Chemical changes are not easily reversible.

In conclusion, physical changes do not produce new substances while chemical changes produce new substances.

Learn more about physical and chemical changes at: brainly.com/question/18526179

#SPJ1

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The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th
MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

\frac{K_1}{K_2}=?

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate constant reaction -1

K_1 = rate constant reaction -2

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = 25^oC=273+25=298 K

Now put all the given values in this formula, we get

\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340

0.4284 is the ratio of the rate constants.

7 0
3 years ago
A cube has an edge length of 9 cm .
Angelina_Jolie [31]

Answer:

9^3 i think so like 279

Explanation:

blah

5 0
3 years ago
What Element am I?
LiRa [457]

Answer:

Nitrogen

Explanation:

Nitrogen has 5 Valence Electrons.

And its atomic mass is also less than Bismuth.

There are other elements in the 5th row but this one has the lowest atomic mass compared to the others.

7 0
3 years ago
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Varvara68 [4.7K]

Answer:

dolo HAHAHAAHAHHAHAHAHA

6 0
3 years ago
Please help! 10 points!!
klemol [59]
Hi,
The answer is HF since hydrogen bonds are can be formed only between Hydrogen and Fluorine, Oxygen or Nitrogen.
8 0
3 years ago
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