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3 years ago

Please help

Chemistry

2 answers:

lana66690 [7]3 years ago

7 0

Bro i don’t even know sorry mannnnnnnnnnn

kow [346]3 years ago

5 0

Answer:

plsss help me and modules

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A mixture of gases with a pressure of 800.0 mm hg contains 60% nitrogen and 40% oxygen by volume. what is the partial pressure o

klasskru [66]

Hello!

We have the following statement data:

Data:
$P_{Total} = 800 mmHg$
$P\% N_{2} = 60\%$
$P\% O_{2} = 40\%$
$P_{partial} = ? (mmHg)$

As the percentage is the mole fraction multiplied by 100:

 $P = X_{ O_{2} }*100$

The mole fraction will be the percentage divided by 100, thus:
What is the partial pressure of oxygen in this mixture?

$X_{ O_{2} } = \frac{P}{100}$
$X_{ O_{2}} = \frac{40}{100}$
$\boxed{X_{ O_{2}} = 0.4}$

To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:

In relation to $O_{2}$ :

$\frac{P O_{2} }{P_{total}} = X_O_{2}$
$\frac{P O_{2} }{800} = 0.4$
$P_O_{2} = 0.4*800$
$\boxed{\boxed{P_O_{2} = 320\:mmHg}}\end{array}}\qquad\quad\checkmark$

Answer:
b. 320.0 mm hg

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3 years ago

In order to promote the common ion effect, the concentration of the common ion must first:_____.

Svet_ta [14]

We need to increase the concentration of common ion first, in order to promote the common ion effect

<h3>What is the Common ion effect?</h3>

It is an effect that suppresses the dissociation of salt due to the addition of another salt having common ions.

For example, a saturated solution of silver chloride in equilibrium has Ag⁺ and Cl⁻ . Sodium Chloride is added to the solution and has a common ion Cl⁻. As a result, the equilibrium shifts to the left to form more silver chloride. Thus, solubility of AgCl decreases.

The Equilibrium law states that if a process is in equilibrium and is subjected to a change

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the concentration of reactant or product,

then the equilibrium shifts in a particular direction, according to the condition.

Thus, an increase in the concentration of common ion promotes the common ion effect.

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How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?

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The grams of glucose are needed to prepare 400g of a 2.00%(m/m) glucose solution g is calculated as below

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