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Ilya [14]
3 years ago
14

Please help

Chemistry
2 answers:
lana66690 [7]3 years ago
7 0
Bro i don’t even know sorry mannnnnnnnnnn
kow [346]3 years ago
5 0

Answer:

plsss help me and modules

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A match has about 21 milligrams of red phosphorus coating the tip. How many atoms of phosphorus is this?
MAXImum [283]

Answer:

4.083 * 10^20 atoms.

Explanation:

One Mole of phosphorus  contains 6.022 * 10^23 atoms (Avogadros number)'

Since 1 mole of Phosphorus  has a mass of  30.974 grams, 21 milligrams has

6.022 * 10^23  * 0.021 / 30.974

= 0.004083 * 10^23

= 4.083 * 10^20

3 0
3 years ago
Nuclei with ______ numbers of neutrons and protons are more stable . A low
FinnZ [79.3K]

Answer: equal

Explanation:

I believe the answer is equal but i would need more context.

7 0
3 years ago
Balancing out Fe +h2O fe3O4 +H2
Katyanochek1 [597]
3Fe + 4H2O (yields) Fe3O4 + 4H2
4 0
3 years ago
A reaction has activation energy of 85kjper mol. What is the effect on the rate of raising the temperature from 20degree to 30 d
DENIUS [597]

Answer: The rate increases 3 times on raising the temperature from 20degree to 30 degree​

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]

where k_2 = rate constant at temp T_2

k_1 = rate constant at temp T_1

E_a= activation energy

R= gas constant

T_1= temperature = 20^0C=(20+273)K=293K

T_2= temperature = 30^0C=(30+273)K=303K

ln \frac{k_{2}}{k_{1}} = \frac{-85\times 1000J/mol}{8.314J/Kmol}[\frac{1}{303} - \frac{1}{293}]

ln \frac{k_{2}}{k_{1}}=1.15

\frac{k_{2}}{k_{1}}=3

Thus rate increases 3 times on raising the temperature from 20degree to 30 degree​

3 0
3 years ago
How do magnetic forces repel or attract? make it short and simple 25 points
stiks02 [169]

Answer:

When you place the north pole of one magnet near the south pole of another magnet, they are attracted to one another.

Explanation:

6 0
3 years ago
Read 2 more answers
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