Answer:
34.83% probability that the proportion of invoices in the sample is less than 18%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
For a proportion p in a sample of size n, we have that
In this problem, we have that:
So
What is the probability that the proportion of invoices in the sample is less than 18%?
This is the pvalue of Z when X = 0.18. So
has a pvalue of 0.3483
34.83% probability that the proportion of invoices in the sample is less than 18%
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Hope this helps!
Answer:
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A: South America..................
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