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Yanka [14]
2 years ago
8

A balloon filled with 1.92 g of helium has a volume of 12.5 L. What is the balloon’s volume after 0.850 g of helium has leaked o

ut through a small hole (assume constant pressure and temperature)?
Chemistry
1 answer:
Marizza181 [45]2 years ago
8 0

The answer is 1.56L. Avogadro's Law states that the volume of a gas is directly proportional to the number of moles (or a number of particles) of gas when the temperature and pressure are held constant.

V∝n

V₁/n₁m= V₂/n₂

V₁ = initial volume of gas  = 12.5 L

V₂ = final volume of gas = ?

n₁ = initial moles of gas  = 0.016 mole

n₂ = final moles of gas  = 0.016-0.007 = 0.002 mole

V₁/n₁m= V₂/n₂

V₂= 1.56L

Avogadro's Law is in evidence whenever you blow up a balloon. The volume of the balloon increases as you add moles of gas to the balloon by blowing it up.

Learn more about Volume here:

brainly.com/question/5018408

#SPJ4

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Answer : The vapor pressure of solution is 23.67 mmHg.

Solution:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

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where,

p^o = vapor pressure of pure solvent  (water) = 23.76 mmHg

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w_2 = mass of solute  (sucrose) = 12.25 g

w_1 = mass of solvent  (water) = 176.3 g

M_1 = molar mass of solvent (water) = 18.02 g/mole

M_2 = molar mass of solute (sucrose) = 342.3 g/mole

Now put all the given values in this formula ,we get the vapor pressure of the solution.

\frac{23.76-p_s}{23.76}=\frac{12.25\times 18.02}{176.3\times 342.3}

p_s=23.67mmHg

Therefore, the vapor pressure of solution is 23.67 mmHg.

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