In class we derived the Gibbs energy of mixing for a binary mixture of perfect gases. We also discussed that the same result is
1 answer:
Answer:
Attached below
Explanation:
Free energy of mixing = ΔGmix = Gf - Gi
attached below is the required derivation of the
<u>a) Molar Gibbs energy of mixing</u>
ΔGmix = Gf - Gi
hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )
<u>b) molar excess Gibbs energy of mixing</u>
Ni = chemical potential of gas
fi = Fugacity
N°i = Chemical potential of gas when Fugacity = 1
ΔG = RT In ( a2 / a1 )
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Answer:- New pressure is 0.942 atm.
Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.
Pressure is directly proportional to the kelvin temperature. The equation used here is:
Where, and
are initial and final temperatures,
and
are initial and final pressures.
= 20.3 + 273.15 = 293.45 K
= -2.0 + 273.15 = 271.15 K
= 1.02 atm
= ?
Let's plug in the values in the equation and solve it for final pressure.
= 0.942 atm
So, the new pressure of the jar is 0.942 atm.