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3 years ago

Chemists use activity series to determine wether which type of reaction will occur?

1 answer:

5 0

<h2>Chemists use activity series to determine whether A SINGLE REPLACEMENT reaction will occur.</h2>

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When 2.00 kJ of energy is transferred as heat to nitrogen in a cylinder fitted with a piston with an external pressure of 2.00 a

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Answer: B

Explanation:

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3 years ago

Which element(s) are not balanced in this equation ?

Alekssandra [29.7K]

Only the Fe is unbalanced.
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3 years ago

Read 2 more answers

Define the term relative atomic mass, A.

Naily [24]

The mass of an atom and the equivalent of to the number of protons and neutrons in the atom

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3 years ago

From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

Answer: The concentration of $NH_3$ required will be 0.285 M.

Explanation:

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

7 0

3 years ago

If you had 15 molecules of H2 and an unlimited supply of N2, how many

Masja [62]

Answer:

10 molecules of NH₃.

Explanation:

N₂ + 3H₂ --> 2NH₃

As the N₂ supply is unlimited, what we need to do to solve this problem is convert molecules of H₂ into molecules of NH₃. To do so we use the stoichiometric coefficients of the balanced reaction:

15 molecules H₂ * $\frac{2moleculesNH_3}{3moleculesH_2}$ = 10 molecules NH₃

10 NH₃ molecules could be prepared from 15 molecules of H₂ and unlimited N₂.

8 0

3 years ago