Shielding electrons are the electrons in the energy levels between the nucleus and the valence electrons. They are called "shielding" electrons because they "shield" the valence electrons from the force of attraction exerted by the positive charge in the nucleus. Hope this helps!!
Answer : The volume of
produced at standard conditions of temperature and pressure is 0.2422 L
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
= initial pressure of
gas = (740-22.4) torr = 717.6 torr
= final pressure of
gas at STP= 760 torr
= initial volume of
gas = 280 mL
= final volume of
gas at STP = ?
= initial temperature of
gas = ![25^oC=273+25=298K](https://tex.z-dn.net/?f=25%5EoC%3D273%2B25%3D298K)
= final temperature of
gas = ![0^oC=273+0=273K](https://tex.z-dn.net/?f=0%5EoC%3D273%2B0%3D273K)
Now put all the given values in the above equation, we get:
![\frac{717.6torr\times 280mL}{298K}=\frac{760torr\times V_2}{273K}](https://tex.z-dn.net/?f=%5Cfrac%7B717.6torr%5Ctimes%20280mL%7D%7B298K%7D%3D%5Cfrac%7B760torr%5Ctimes%20V_2%7D%7B273K%7D)
![V_2=242.2mL=0.2422L](https://tex.z-dn.net/?f=V_2%3D242.2mL%3D0.2422L)
Therefore, the volume of
produced at standard conditions of temperature and pressure is 0.2422 L
Answer:
1. bitter
2. turns litmus paper red
3. oxygen, hydrogen, and molecules.
Explanation:
Q=m(c∆t +heat of fusion + heat of evaporation)
m= 44g
c= 4.186 J/g.C
∆t= 107-(-8) =115 C
heat of fusion= 333.55 J/g
heat of evaporation=2260 J/g
Q=44(4.186*115 + 333.55 + 2260)
Q= 135297.36 J
<u>Answer:</u> The element represented by M is Strontium.
<u>Explanation:</u>
Let us consider the molar mass of metal be 'x'.
The molar mass of MO will be = Molar mass of oxygen + Molar mass of metal = (16 + x)g/mol
It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:
![\frac{15.44}{100}\times (x+16)=16g/mol\\\\(x+16)=\frac{16g/mol\times 100}{15.44}\\\\x=(103.626-16)g/mol\\\\x=87.62g/mol](https://tex.z-dn.net/?f=%5Cfrac%7B15.44%7D%7B100%7D%5Ctimes%20%28x%2B16%29%3D16g%2Fmol%5C%5C%5C%5C%28x%2B16%29%3D%5Cfrac%7B16g%2Fmol%5Ctimes%20100%7D%7B15.44%7D%5C%5C%5C%5Cx%3D%28103.626-16%29g%2Fmol%5C%5C%5C%5Cx%3D87.62g%2Fmol)
The metal atom having molar mass as 87.62/mol is Strontium.
Hence, the element represented by M is Strontium.