Answer:
a) 16.4 m/s
b) 16.4 m/s
c) 16.4 m/s
Explanation:
a)
m = mass of the snowball = 0.690 kg
h = height of the cliff = 8.25 m
v₀ = initial speed of ball at the time of launch = 10.3 m/s
v = speed of the ball as it reach the ground
Using conservation of energy
initial kinetic energy + initial potential energy at the cliff = final kinetic energy just before reaching the ground
(0.5) m v₀² + mgh = (0.5) m v²
(0.5) v₀² + gh = (0.5) v²
(0.5) (10.3)² + (9.8 x 8.25) = (0.5) v²
v = 16.4 m/s
b)
As the launch angle is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the angle of launch.
v = 16.4 m/s
c)
As the mass is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the mass of the ball.
v = 16.4 m/s
For a neutral atom number of electrons equals number of protons, in other for the net charge of the atom to be zero...
no. of electrons = 12
Answer:
F = 29.9 N
Explanation:
It is given that, The Sun exerts a gravitational force of 29.9 N on a rock that's located in a river bed here on Earth. We need to find the gravitational force the rock exert on the Sun. It is a case of Newton's third law of motion which states that the force acting from one object to another is equal to the force acing from second object to the first object and the two forces must be in opposite direction. Hence, the gravitational force the rock exert on the Sun is same i.e. 29.9 N.
