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2 years ago

Electronic bulletin boards, combining the

Mathematics

1 answer:

snow_lady [41]2 years ago

7 0

(D) "subjects as diverse as"

"As...as" is the proper construct to employ when comparing items that are equal in some sense, therefore using "as" in this context is inappropriate (which is what happens in the sentence) So, the correct response is D.

Choice (A) uses awkward wording. As demands "such" come before it. Option (B) uses awkward wording. Should read "such as," not "that are." An incorrect idiom is present in Option (C).

It should be "diversity such as," not "such diversity." There is an agreement issue with Option (E) (in number). The various subjects mentioned cannot be referred to as "a subject".

Here's a question with an answer similar to this about improper phrasing: brainly.com/question/15806900

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If a(n)=24 which recursive formula could represent the sequence below? ...,24,88,664,8408,...

sesenic [268]

24= 3*2^3
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)

8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)

So:
a(n) = a(n-1) + a(n-2)^2

Lets check: 88+24^2= 664
664+88^2= 8408

3 1

3 years ago

You buy a pair of jeans that cost $48 and a shirt for $22, how much will you pay with 6% sales tax?

Debora [2.8K]

U will pay $74.20

Total is 70 and tax is 6 % so 70*1.06

5 0

3 years ago

Read 2 more answers

Question 2

prisoha [69]

Answer:

Please check the explanation.

Step-by-step explanation:

Calculating the area of the outer rectangle:

Given

The length outer rectangle = l = 3x - 1

The width of outer rectangle = w = 5x + 2

Thus,

The area of the outer rectangle:

$A = wl$

$= (5x + 2) (3x - 1)$

$=5x\cdot \:3x+5x\left(-1\right)+2\cdot \:3x+2\left(-1\right)$

$=5\cdot \:3xx-5\cdot \:1\cdot \:x+2\cdot \:3x-2\cdot \:1$

$=15x^2+x-2$

Calculating the area of the inner rectangle:

Given

The length inner rectangle = l = x + 7

The width of inner rectangle = w = x

Thus,

The area of the outer rectangle:

A = wl

= x(x+7)

= x² + 7

Calculating the area of the shaded region:

The area of the outer rectangle = 15x² + x - 2

The area of the inner rectangle = x² + 7

The area of the shaded region can be determined by subtracting the area of the inner rectangle from the area of the outer rectangle.

Thus,

shaded region Area = Outer Rectangle Area - Inner Rectangle Area

= 15x² + x - 2 - (x² + 7)

= 15x² + x - 2 - x² - 7

= 14x² + x - 9

Therefore, the Area of the shaded region is: 14x² + x - 9

4 0

3 years ago

8. 2²=1 o=0 z= + The solutions are and

natka813 [3]

Step-by-step explanation:

the question is z²=1

taking square root on both sides

√z² = √1

the square root and the square cancel out each other

it gives

z=±1

that means either z=+1 or z=-1

so the solutions are 1 and -1

8 0

4 years ago

Solve each equation.SHOW work plz

Studentka2010 [4]

$3 \frac{1}{2} r = 28 \\ \frac{7}{2} r = 28 \\ \frac{ \frac{7}{2} }{ \frac{7}{2} } r = \frac{28}{ \frac{7}{2} } \\ r = \frac{ \frac{56}{2} }{ \frac{7}{2} } \\ r= \frac{56}{7}$

$1 \frac{1}{2} c =6 \\ \frac{3}{2} c= \frac{12}{2} \\ \frac{ \frac{3}{2} }{ \frac{3}{2} } c= \frac{ \frac{12}{2} }{ \frac{3}{2} } \\ c= \frac{ \frac{12}{2} }{ \frac{3}{2} } = \frac{12}{3} =4 \\ c=4$

7 0

3 years ago