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nlexa [21]
1 year ago
8

Classify each of the following statements as a characteristic (a) of electric forces only, (b) of magnetic forces only, (c) of b

oth electric and magnetic forces, or (d) of neither electric nor magnetic forces. (viii) The magnitude of the force depends on the charged object's direction of motion.
Physics
1 answer:
kakasveta [241]1 year ago
5 0

(b) Magnetic forces only

When an object is placed in an electric field it experiences an electric force given by :

F_{E} = |q| × E

Similarly when it is placed in a magnetic field it experiences a magnetic force given by :

F_{B} = |q|×v×Bsinθ

When a particle is placed in electric field the particle gets accelerated.

The electric field has a direction, positive to negative. This is the direction that the electric field will cause a positive charge to accelerate. For example If a positive charge is moving in the same direction as the electric field vector the particle's velocity will increase. If it is moving in the opposite direction it will decelerate.  ( No change in direction of motion in this case)

When a particle is moved in magnetic field ,the magnetic force is perpendicular to velocity and magnetic field . Since force is perpendicular to velocity ,it only changes the direction of motion.

To know more about electric and magnetic forces kindly refer to the below link:

brainly.com/question/1594186

#SPJ4

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Two balls of equal mass collide and stick together as shown in the figure. The initial velocity of ball B is twice that of ball
Mice21 [21]

The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as

  • \theta f = 26.3 \deg
  • vf/vA= 0.94
  • 2vf^2 / 5vA^2 = 0.35

<h3>What is  Collison equilibrium?</h3>

According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.

Generally, the equation for Collison equilibrium is  mathematically given as

For horizontal motion

mvAx+m2vAx = 2mvfx

For vertical motion

-mvAy+m2vAy = 2mvfy

vfy = 1/2 vAy

\tan \theta f = vfy/vfx \\\\\tan \theta f = 1/3 vAy/vAx \\\\\tan \theta f  = vAy/vAx \\\\\theta f = tan-1 ( 1/3 tan (56) )\\\\

\theta f = 26.3 \deg

(b)

v fy = vf sin \theta f\\\\vAy = vA sin theta i\\\\vf/vA = vfy/vAy sin( \theta i)/sin(\theta f)\\\\vf/vA = 1/2 sin(56)/sin(26.3) \\\\

vf/vA= 0.94

(c)

Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}

2vf^2 / 5vA^2 = 0.35

In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others

\theta f = 26.3 \deg

vf/vA= 0.94

2vf^2 / 5vA^2 = 0.35

Read more about collision theory

brainly.com/question/20628781

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8 0
2 years ago
A rower in a boat pushes the water using an oar.
brilliants [131]

Answer:

It's B, because of process of elimination:

A: The rower would be applying force to the oar not the other way around. So that's immediately out.

C: If the force of the oar applies to the water, the force of the water cannot apply to the oar.

D: Same as why A is incorrect.

So B is the only one left.

6 0
3 years ago
Read 2 more answers
A molecule of roughly spherical shape has a mass of 6.10 × 10-25 kg and a diameter of 0.70 nm. The uncertainty in the measured p
Ilia_Sergeevich [38]

Answer:

\Delta v = 0.123 m/s

Explanation:

As per the law of uncertainty we know that

\Delta p \times \Delta x = \frac{h}{4\pi}

now we know that

\Delta x = 0.70 nm

m = 6.10 \times 10^{-25}

also we have

h = 6.626 \times 10^{-34} J.s

now we will have

m\Delta v \times \Delta x = \frac{h}{4\pi}

(6.10 \times 10^{-25})\Delta v \times (0.70 \times 10^{-9}) = \frac{6.626 \times 10^{-34}}{4\pi}

\Delta v= 0.123 m/s

4 0
3 years ago
the sole of a tennis shoe has a surface area of 0.0290 m^2. if it is worn by a 65.0 kg person, what pressure does the shoe exert
AURORKA [14]

Answer: 21965.517 Pa

Explanation:

Pressure P is the force F exerted by a gas, a liquid or a solid on a surface (or area) A, its unit is Pascal Pa which is equal to N/m^{2} and its formula is:  

P=\frac{F}{A} (1)

In this case we have the surface of a sole of a tennis shoe:

A=0.0290 m^{2} (2)

And the mass m of the person who wears it:

m=65 kg

On the other hand, we know the weight is the force  F the Earth exerts on people and objects due gravity g :

F=m.g=(65 kg)(9.8m/^{2})

F=637N (3)

Substituting (2) and (3) in (1):

P=\frac{637N}{0.0290 m^{2}} (4)

Finally:

P=21965.517 Pa This is the pressure the shoe exert on the ground

5 0
2 years ago
Fill in the blank.
Fofino [41]
It would decrease, hope it helps
8 0
2 years ago
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