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Marina CMI [18]
3 years ago
12

The pressure on a fluid at rest in a pipe increases by 20 Pa. How does this change in pressure affect the pressure on the fluid

in the rest of the pipe
Physics
1 answer:
timofeeve [1]3 years ago
4 0

Answer:The change in pressure can affect the pressure on the fluid through the radius and diameter of the pipe.

r^² x Pressure (pa).

Therefore the narrower the other part of the pile, the greater the pressure on the fluid at such part, the wider in other part the lesser the pressure on the fluid at this part.

Explanation:

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A uniform rod is 2.0 m long. The rod is pivoted about a horizontal, frictionless pin through one end. The moment of inertia of t
emmasim [6.3K]

Answer:

Angular acceleration = 6.37rad/sec²

Approximately, Angular acceleration =

6.4 rad/sec²

Explanation:

Length of the rod = 2.0m long

Inclination of the rod (horizontal) = 30°

Mass of the rod is not given so we would refer to it as = M

Rotational Inertia of the Rod(I) = 1/3ML²

Angular Acceleration = ?

There is an equation that shows us the relationship between Torque and Angular acceleration.

The equation is :

Torque(T) = Inertia × Angular Acceleration

Angular acceleration = Torque ÷ Inertia

Where:

Torque = L/2(MgCosθ)

Where M = Mass

L = Length = 2.0m

θ = Inclination of the rod (horizontal) = 30°

g = Acceleration due to gravity = 9.81m/s²

Inertia = 1/3ML²

Angular Acceleration =  (Mass × g × Cos (30°) × (L÷2)) ÷ 1/3ML²

Angular Acceleration =

(3 × g × cos 30°) ÷ 2× L

Angular Acceleration = (3 × 9.81m/s² × cos 30°) ÷ 2× L

Angular Acceleration = 3 × 9.81m/s² × cos 30°) ÷ 2× 2.0m

Angular Acceleration = 6.37rad/sec²

Approximately Angular Acceleration =

6.4rad/sec²

5 0
3 years ago
According to the Can Manufacturers Institute, the energy used to make an aluminum can from recycled aluminum is 5% of the energy
ololo11 [35]

Answer:

H = 109.2 TJ.

Explanation:

Please see the attachment below.

4 0
3 years ago
Physical properties for soap
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Answer:

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2 years ago
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A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow
trapecia [35]

Answer:N=13.53 rpm

Explanation:

Given

radius r=7.80 m

Centripetal acceleration a_c=1.6 g

and centripetal acceleration a_c=\omega ^2r

where \omega =angular\ velocity

1.6\times 9.8=\omega ^2\times 7.8

\omega ^2=2.0102

\omega =1.417 rad/s

and  \omega =\frac{2\pi \cdot N}{60}

1.417\times 60=2\pi \cdot N

N=13.53 rpm

8 0
3 years ago
Define resistance of a conductor. State the factors on which resistance of a conductor depends.
e-lub [12.9K]
<h3>Answer:</h3>

1. Resistance is the opposition offered in a path of flow of current by the atoms or molecules of the conductor.

Factors on which resistance of a conductor depends are:

<h3 />
  • Length R \propto l

  • Area of cross section R \propto \dfrac{1}{A}

  • Nature of the material

2. Rheostat is used to change the resistance without changing the voltage source in an electric circuit.

3.

Given :

\dashrightarrow  l = 50 m

\dashrightarrow  A = 0.01 {mm}^{2}

\dashrightarrow  A = 0.01 \times  {10}^{ - 6}  \:  {m}^{2}

\dashrightarrow   \rho = 5 \times  {10}^{ - 8}          \: \Omega \: m

We know that,

\dashrightarrow  R =  \rho \dfrac{l}{A}

\dashrightarrow  R =  5  \times  {10}^{ - 8} \bigg(\dfrac{50}{0.01 \times  {10}^{ - 6} } \bigg)

\dashrightarrow  { \pink{ \underline{ R = 250  \: \Omega }}}

5 0
2 years ago
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