Answer:
a) w = 9.599 10⁴ rad / s
, b) v = 3.35 10¹⁶ m / s
, c) a = 3.22 10²¹ m / s²
Explanation:
For this exercise we must use the relation of angular kinematics
a) angular velocity, the distance remembered in orbit between time (period)
w = 2π r / T
w = 2 π 3.59 10¹¹ / 2.35 10⁷
w = 9.599 10⁴ rad / s
b) linear and angular velocity are related by the equation
v = w r
v = 9,599 10⁴ 3.49 10¹¹
v = 3.35 10¹⁶ m / s
c) the centripetal acceleration is
a = v² / r = w² r
a = (9,599 10⁴)² 3.49 10¹¹
a = 3.22 10²¹ m / s²
Answer:
decantation, distilling, freezing
Answer:
3.6*10^18s
Explanation:
To find the period of the satellite
We need to apply kephler's third law
Which is
MP² = (4π²/G) d³
d=semi-major axis which is the distance from center of moon = 98km+1740km = 1838km
where M= mass of the moon = 7.3x10^22kg
P=period
G=newtonian gravatational constant= 6.67x10^-11
To find the Period solve for P
P = √[(4π²/G M)xd³]
P=√(4 π²/6.67x10^-22*7.3x10^22kg) x (1.838x10^6m)³]
= 3.6*10^18s
Answer:
The magnitude of the acceleration is 
The direction is
i.e the negative direction of the z-axis
Explanation:
From the question we are that
The mass of the particle 
The charge on the particle is 
The velocity is 
The the magnetic field is 
The charge experienced a force which is mathematically represented as

Substituting value



Note :

Now force is also mathematically represented as

Making a the subject

Substituting values



Answer:
A. Gamma rays have higher energy than microwaves because gamma rays have shorter wavelengths.
Explanation:
Electromagnetic waves are waves produced by the interaction between both magnetic and electric fields. These waves have some properties that make them to be arranged in a definite form producing an electromagnetic spectrum.
The spectrum has a general property of which as the wavelength of the waves increases, the frequency decreases. And vice versa.
Thus, the energy of the waves increases as the frequency increases.
Gamma rays have higher frequency, but shorter wavelength. While microwaves has lower frequency, but higher wavelength.