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topjm [15]
3 years ago
13

The human eye can change the shape of its crystalline lens, and thus modify the lens strength (a.k.a., lens power) of the eye in

order to bring things at different distances from the observer into sharp focus on its retina. If the total effective lens strength (a.k.a., lens power) of a human's eye at a particular moment is 53.0 D, how far from the eye is the object that is currently in focus on the retina
Physics
1 answer:
Softa [21]3 years ago
5 0

Answer:

Good Luck!

Explanation:

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How do we determine the age of rocks and other geologic features?
Mamont248 [21]

Answer:To establish the age of a rock or a fossil, researchers use some type of clock to determine the date it was formed. Geologists commonly use radiometric dating methods, based on the natural radioactive decay of certain elements such as potassium and carbon, as reliable clocks to date ancient events.

Explanation:

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How far is the Earth from the Sun?
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29.5 inches is _______ meters. 74.9 74.9 11.6 11.6 0.749 0.749 0.116
Valentin [98]

Answer:

0.749 m

Explanation:

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5 0
3 years ago
If the rest energies of a positive sigma particle and a lambda particle are 1189.4 and 1115.7 Mev respectively, what is the diff
Lunna [17]

Answer:

1.31022×10⁻³⁴ kg

Explanation:

Difference in energies = 1189.4-1115.7 MeV = 73.7 MeV

Convert this energy to Joules

1 MeV = 1.6×10⁻¹⁹ J

73.7 MeV = 73.7×1.6×10⁻¹⁹ J = 117.92×10⁻¹⁹ J

c = Speed of light = 3×10⁸ m/s

From Einstein's equation

E = mc²

m=\frac{E}{c^2}\\\Rightarrow m=\frac{117.92\times 10^{-19}}{(3\times 10^8)^2}\\\Rightarrow m=1.31022\times 10^{-34}\ kg

∴ Difference in their masses is 1.31022×10⁻³⁴ kg

8 0
3 years ago
A tennis ball bounces on the floor three times. If each time it loses 11% of its energy due to heating, how high does it rise af
aalyn [17]

Answer:

h = 3.10 m

Explanation:

As we know that after each bounce it will lose its 11% of energy

So remaining energy after each bounce is 89%

so let say its initial energy is E

so after first bounce the energy is

E_1 = 0.89 E

after 2nd bounce the energy is

E_2 = 0.89(0.89 E)

After third bounce the energy is

E_3 = (0.89)(0.89)(0.89)E

here initial energy is given as

E = mgH_o

now let say final height is "h" so after third bounce the energy is given as

E_3 = mgh

now from above equation we have

mgh = (0.89)(0.89)(0.89)(mgH)

h = 0.705H

h = 0.705(4.4 m)

h = 3.10 m

3 0
3 years ago
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