2 years ago

What is the 3 word definition for momentum?

Physics

2 answers:

allsm [11]2 years ago

8 0

Momentum can be defined as “mass in motion”

Nesterboy [21]2 years ago

3 0

Answer:

mass multiplied by velocity (4 words but uh

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A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical

Tanya [424]

Answer:

1 m = 39.37 in = 39.37/12 ft = 3.28 ft

V = 1145 k/hr = 1145k/hr * 6076 ft/k = 6957020 ft / hr

V = 6957020 ft/hr / 3600 s/hr = 1933 ft/sec

V = 1933 ft/sec / (3.28 ft / m) = 589 m/s

Check:

88 ft/sec = 60 mph

(1145 k/hr * 6076 ft / k) 3600 sec/hr = 1933 ft/sec = 589 m/s

1933 ft/sec / (88 ft/sec) * 60 mph = 1318 mph

Also, 1318 / 1145 = 6076 / 5280 as it should

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2 years ago

Caculate the total charge transferred through a wire carrying a current of 0.5 Ameter for a period of 20 seconds.

Marina CMI [18]

charge = current x time = 0.5x 20=10Coulombs

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3 years ago

A soccer ball collides with another soccer ball at rest. the total momentum of the balls

Juliette [100K]

I am pretty sure the answer is C.

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3 years ago

Technician A says that the battery must be in good condition and at least 75% charged to accurately test an alternator. Technici

aalyn [17]

Answer:Technician A

Explanation:

Technician A statement is correct as

The battery is required to start the vehicle which, in effect, rotates the alternator at sufficient speed to keep the battery charged. This means if the battery is low it is not possible to start the vehicle and thus we are unable to test the alternator.

That is the battery is pre-requisite to test the alternator. So the battery must be at least a 75 % charge to test the alternator.

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3 years ago

The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc

Law Incorporation [45]

The gravitational force between two objects is given by:
$F=G \frac{m_1 m_2}{r^2}$
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

The distance of the telescope from the Earth's center is $r=6940 km=6.94 \cdot 10^6 m$ , the gravitational force is $F=9.21 \cdot 10^4 N$ and the mass of the Earth is $m_1=5.98 \cdot 10^{24} kg$ , therefore we can rearrange the previous equation to find m2, the mass of the telescope:
$m_2 = \frac{Fr^2}{Gm_1}= \frac{(9.21 \cdot 10^4 N)(6.94\cdot 10^6)^2}{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})} =11121 kg$

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3 years ago

Read 2 more answers