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vekshin1
2 years ago
9

A copper block weighing 2 kg is dropped from a height of 20m. what is the rise in the temperature of the copper block after it h

its the floor. the specific heat capacity of copper is 400 j/(kgc )
Physics
1 answer:
finlep [7]2 years ago
4 0

The rise in temperature is 0.49°c

<h3>What is specific heat capacity?</h3>

The quantity of heat energy needed to raise a substance's temperature per unit of mass is known as specific heat capacity. A material's specific heat capacity is a physical characteristic. Since its value is inversely correlated with the size of the system under study, it is also an illustration of an extended feature.

<h3>what is law of conservation of energy?</h3>

Energy can only be transformed from one form to another. It cannot be created or destroyed

<h3>How will this question be solved?</h3>

From law of conservation of energy we know,

Potential energy of the block= cmΔT

mgh= cmΔT

m×9.8×20= 400×m×ΔT

196=400ΔT

ΔT=0.49°C

To know more about specific heat capacity visit:

brainly.com/question/2530523

#SPJ4

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#4<br> HELP PLEASE!<br> Find Gravitational Potential Energy! <br> THANK YOU!
Scilla [17]

Answer:

\Delta GPE=-3.92\ 10^9\ J

Explanation:

<u>Gravitational Potential Energy</u>

It's the capacity of an object to do work due to its relative height from a fixed reference point.

It's computed as

GPE=m.g.h

Where m is the mass of the object, h is its height and g is the acceleration of gravity, g=9.8 m/sec^2

The mass of water is given as

m=8,000,000\ kg

The height above the rocks is h=50 m. Let's compute the GPE

GPE_1=(8,000,000\ kg)(9.8\ m/s^2)(50\ m)

GPE_1=3,920,000,000\ Joule

It should be expressed in scientific notation

GPE_1=3.92\ 10^9\ J

The GPE at the bottom, where h=0

GPE_2=0

The change of gravitational potential energy is:

\Delta GPE=GPE_2-GPE_1

\boxed{\Delta GPE=-3.92\ 10^9\ J}

8 0
3 years ago
Calculate the net force on particle qi.
aksik [14]

Answer:

-12.12

Explanation:

i just added them together and it worked.

4 0
2 years ago
Change in velocity divided by time. Rate of change of velocity of an object
trapecia [35]
I think it is acceleration
4 0
4 years ago
At a busy intersection, a 1320-kg car traveling west with a speed of 12 m/s collides head-on with a minivan traveling east with
Elza [17]
p = mv so this question pertains to conservation of momentum.

The momentum of the car is 1320*12 = 15840kgms^-1
For the sake of easiness and the fact negatives are annoying, I will assume east to be positive.

So we know 9.4m - 15840 = (1320+m)*1.5
9.4m - 15840 = 1980+1.5m

Rearranging to solve for m
7.9m = 17820
m = 2255.70 = 2300kg to 2sf

7 0
4 years ago
1. An object is moving in a straight line at constant speed. Which of the following is true?
liberstina [14]

c. II and III only (the object has 0 acceleration and the object has  constant velocity.)

Why?

Let's discard each of the given options to find the correct one(s).

<h3>- There are no forces acting on the object:</h3>

False, if an object has a constant speed, it does not mean that there are no forces acting on it, in fact, there will be always acting forces, like frictional force, gravity force, air resistance, and others.

<h3>- The object has a 0 acceleration:</h3>

True, in an object is moving at constant speed, it means that there is no acceleration, the speed will be the same all the time during motion.

<h3>- The object has constant velocity:</h3>

True, <u>if an object is moving in a straight line at constant speed</u> the velocity will be also constant. The velocity of an object is referring to its speed and its direction, if the object is moving in a straight line, the direction will be the same, so, if the speed is constant, the velocity will be also constant.

Have a nice day!

3 0
3 years ago
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