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aliya0001 [1]
3 years ago
7

The _______ are found on the right side of the arrow in a chemical reaction. A. reactants B. products C. subscripts D. coefficie

nts Reset
Chemistry
2 answers:
julia-pushkina [17]3 years ago
8 0

Answer:

B. products are found on the write side of the arrow in a chemical reaction.

ira [324]3 years ago
5 0
<h2>The answer is B. Products</h2><h3>Explanation: The products are found on the right side of the arrow in a chemical reaction. </h3><h3> </h3><h3>In a chemical reaction, the products are the substances that are formed, and are found on the right side of the arrow. The reactants are the substances that are broken apart or combined to form the products, and are found on the left side of the arrow.</h3>
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Which type of society survives mainly by foraging for food?
Dennis_Churaev [7]
The appropriate answer is a. HUNTER-GATHERER. Hunter-gatherer societies are nomadic and they forage for edible plants, bean, fruits and nuts. They also hunt wild game for food. Early humans in the Neolithic period practiced this way of life. 
Agrarian societies thrive on agriculture which they depend on for sustainable and for trade. Animals and plants are domesticated and so people can settle and build a society. Pastoral agriculture is a semi-nomadic lifestyle where the society is centered around keeping herds of grazing animals. Industrial societies focus on manufacturing and this is the backbone of the society. 
6 0
3 years ago
Find the new pressure of 5 L of a gas at STP that is cooled to 250 K and expanded to 6L
UNO [17]
I’m so sorry i have to do this 5L 24
5 0
3 years ago
The spectrochemical series is I &lt; Br&lt; &lt; Cl^- &lt; F
vfiekz [6]

Answer:

b. The splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.

Explanation:

The spectrochemical series is an arrangement of ligands in increasing order of their magnitude of crystal field splitting.

Ligands that occurs towards the right in the series are called strong field ligands and they tend to cause a greater magnitude of crystal field splitting. Ligands that occur towards the left hand side in the series are called weak field ligands and they tend to cause a lesser magnitude of crystal field splitting.

Since Cl^- is a weak field ligand, it causes a lesser magnitude of d orbital splitting compared to ethylenediammine (en) which causes a greater magnitude of d orbital splitting.

Hence; the splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.

6 0
3 years ago
Use the expression we obtained in class to write the molar absorption coefficient of a particular transition in terms of the tra
Anna007 [38]

Answer:

Initially the function is symmetric with respect to the axis of the one dimensional box. In the final state it is also symmetrical, however you can envision a snapshot of the system as the light field is interacting with the wave-function wherein a node begins to develop as is shown in the middle and the wave function is evolving from the initial to final state. Now consider that the electron density during process is the square of the wave function:

Electron density during transition

As can be seen in the initial and final states the electron density is symmetrically distributed with respect to the axis of the box. However with the field on, the electron density is not symmetrically distributed and a transitory dipole moment can be present. To relate back to real molecules think of each of those orbitals as a linear combination of atomic orbitals. One important factor is the symmetry. But there may be one other factor that will be just as important as symmetry. If you treat orbital 1 as a linear combination over n orbitals and orbital 2 as a linear combinations of orbitals as well, there will be a spatial over lap between the orbital in the ground state and the orbital in the excited state. If there is no spatial overlap between the ground state and excited state orbitals there will be no transition dipole moment. However, if the electrons are in the same place spatially, a large transition dipole moment will result.

Explanation:

4 0
2 years ago
Consider the reaction zn + no− 3 → nh3 + zn(oh)2− 4 carried out in an aqueous basic solution. when the equation is properly bala
Inessa05 [86]
Balancing the reaction is done to obey the law of nature, particularly, the Law of Definite Proportions. The concept is, the amount of the same element before and after the reaction must be the same. This is actually a redox reaction.

Oxidation half-reaction: Zn  + 4 OH⁻ → Zn(OH)₄²⁻ + 2 e-  

Reduction half-reaction: NO₃⁻ + 6 H₂O + 8 e-→ NH₃ + 9 OH⁻

Adding both reaction, we get the overall complete balanced equation:

<span>4Zn + NO</span>₃⁻ + 6 H₂O + 7 OH⁻  → 4 Zn(OH)₄²⁻ + NH₃

Thus, the charge in the product side is 4*-2 = <em>-8</em>.

3 0
3 years ago
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