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Take 23mols and multiply it by the atomic mass of Li:
23mol * 6.94g/mol = 159.62g
Answer:
The molar mass of unknown gas is 145.82 g/mol.
Explanation:
Volume of oxygen gas effused under time t = 8.24 mL
Effusion rate of oxygen gas = 
Molar mass of oxygen gas = 32 g/mol
Volume of unknown gas effused under time t = 3.86 mL
Effusion rate of unknown gas = 
Molar mass of unknown gas = M
Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:




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