Question

A proton is located at a distance of 0.333 m from a point charge of 8.25 pC. The repulsive electric force moves the proton until it is at a distance of 1.64 m from the charge. Suppose that the electric potential energy lost by the system is carried off by a photon that is emitted during the process. What is its wavelength

Answer 1

The wavelength of the proton is $9.8 \times 10^{-12} m$

solution:

$\Delta PE= PE_1-PE_2\\\Delta PE= k\times q\times e( \frac{1}{r_1}- \frac{1}{r_2} )\\\Delta PE = 9 \times10^9\times 8.25 \times 10^-^61.6 \times 10^{-19} \times(\frac 1{0.333} -\frac 1{1.64})\\\Delta PE = 2.01 \times 10^{-14 }J.$

also energy E = $\frac{h \times c}{\lambda}$

$\lambda = \frac{h \times c}{E} \\\lambda = \frac {6.626 \times10^{-34} \times 3 \times10^8}{2.01 \times10^{-14}} =9.8 \times 10^{-12} m$

What is wavelength?

• The distance over which a periodic wave's shape repeats is known as the wavelength in physics.
• It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.
• The spatial frequency is the reciprocal of the wavelength. The Greek letter lambda is frequently used to represent wavelength.
• The term wavelength is also occasionally used to refer to modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.

To learn more about wavelength with the given link

brainly.com/question/12924624

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