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pickupchik [31]
2 years ago
11

Julianne went to a restaurant to have a taste of her favorite fried chicken and spaghetti. She drove 2 km, east and then 8.5 km,

northeast. What is Julianne’s displacement from her origin?
Physics
1 answer:
GREYUIT [131]2 years ago
5 0

Julianne’s displacement from her origin is equal to 10.015 kilometers.

<u>Given the following data:</u>

  • Distance A = 2 km, East.
  • Distance B = 8.5 km, Northeast.

To calculate Julianne’s displacement from her origin:

<h3>How to calculate displacement.</h3>

We would denote the two (2) unit vectors along the East and Northeast directions by i and j respectively.

<u>Note:</u> Northeast is at angle of 45° with the East.

In terms of vectors, the distances becomes:

Distance A = 2i

Distance\;B=8.5 [(cos 45i + sin 45j)]\\\\Distance\;B=(\frac{8.5}{\sqrt{2} } i \;+\;\frac{8.5}{\sqrt{2} } j)

<u>For the </u><u>resultant displacement</u><u>:</u>

D^2 = [(2+\frac{8.5}{\sqrt{2} } )^2+ (\frac{8.5}{\sqrt{2} } )^2\\\\D =\sqrt{[(2+\frac{8.5}{\sqrt{2} } )^2+ (\frac{8.5}{\sqrt{2} } )^2} \\\\D=2+\frac{8.5}{\sqrt{2} } + \frac{8.5}{\sqrt{2} }

D = 10.015 kilometers.

Read more on displacement here: brainly.com/question/13416288

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A physics professor did daredevil stunts in his spare time. His last stunt was an attempt to jump across a river on a motorcycle
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a) 17.8 m/s

b) 28.3 m

Explanation:

Given:

angle A = 53.0°

sinA = 0.8

cosA = 0.6

width of the river,d = 40.0 m,

the far bank was 15.0 m lower than the top of the ramp h = 15.0 m,

The river itself was 100 m below the ramp H = 100 m,

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-h= vsinA\times t-gt^2/2

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-15 = 0.8vt - 4.9t^2  ............. (1)

horizontal displacement d = vcosA×t = 0.6×v ×t

so v×t = d/0.6 = 40/0.6

plug it into (1) and get

-15 = 0.8\times40/0.6 - 4.9t^2

solving for t we get

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(b) If his speed was only half the value found in (a), where did he land?

v = 17.8/2 = 8.9 m/s

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⇒ 4.9t^2 - 8.9\times0.8t - 100 = 0

t = 5.30 s

then

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