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n200080 [17]
2 years ago
5

Light from a 560 nm monochromatic source is incident upon the surface of fused quartz (n=1. 56) at an angle of 60°. what is the

angle of reflection from the surface?
Physics
1 answer:
ankoles [38]2 years ago
7 0

The angle of reflection is "60°".

Here we apply the law of the concept of reflection then we get the final answer easily.

The angle of incident = angle of reflection

Then, the Angle of the incident =60°

What is reflection?

  • Reflection is the phenomenon of light rays returning to the source after striking an obstruction.
  • It resembles the way a ball bounces when we toss it on a hard surface.
  • Some of the light rays that strike an item are reflected, some of them travel through it, and the remainder are absorbed by the object.
  • The given values are:Light from a monochromatic source,= 560 nm
  • The angle of incidence,= 60°
  • The surface of fused quartz (n),= 1.56
  • When a light ray does exist on a flat surface, the law or idea of reflection should apply since it includes both the reflected and "normal" light rays at the mirror surface.
  • According to the above law,Angle of incident = angle of reflection
  • Then, Angle of incident =60°.

To learn more about reflection visit: brainly.com/question/15487308

#SPJ4

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Oliga [24]

Answer:

hsjishhdhjs jdjyshskksndhu

6 0
3 years ago
The pink car has a velocity of 4.4 m/s to the right while the blue car has a velocity of 6.8 m/s to the left. If the two cars cr
aleksley [76]

Given :

The pink car has a velocity of 4.4 m/s to the right while the blue car has a velocity of 6.8 m/s to the left.

To Find :

If the two cars crashed and stuck together, what would their combined momentum be afterwards and what direction would they be moving.

Solution :

Let, combined velocity of the car is v.

Also, let us assume that mass of both the cars are equal and it is m.

By conservation of momentum :

Initial momentum = Final momentum

 m( 6.8 ) - m( 4.4 ) = 2mv

2mv =2.4m

v = 1.2 m/s

Therefore, the velocity of combined car after crash is 1.2 m/s .

4 0
3 years ago
A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball
lora16 [44]

Explanation:

It is given that,

Mass of the ball, m = 0.06 kg

Initial speed of the ball, u = 50.4 m/s

Final speed of the ball, v = -37 m/s (As it returns)  

(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :

J=m(v-u)

J=0.06\times (-37-(50.4))  

J = -5.24 kg-m/s

(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.

W=\dfrac{1}{2}m(v^2-u^2)

W=\dfrac{1}{2}\times 0.06\times ((-37)^2-(50.4)^2)

W = -35.1348 Joules

Hence, this is the required solution.

6 0
4 years ago
A weed eater does 21 kJ of work in 0.750 h. What power does it develop?
myrzilka [38]

Answer:

p =  \frac{w}{t}

21kj÷0.750

28w

6 0
3 years ago
What constant horizontal force is required to drag a 5 kg block along a
BARSIC [14]

Answer:

25N

Explanation:

formula=> Frictional force= coefficient of friction x normal reaction

normal reaction is mass x gravity(10N/kg)

so Frictional force= 0.5x5x10

=25N

but that is the Frictional force not the constant force

to get the constant force, subtract the Frictional force from the weight of the block

weight= mass x gravity

= 5x10

= 50N

50N-25N

=25N

5 0
3 years ago
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