Answer:
hsjishhdhjs jdjyshskksndhu
Given :
The pink car has a velocity of 4.4 m/s to the right while the blue car has a velocity of 6.8 m/s to the left.
To Find :
If the two cars crashed and stuck together, what would their combined momentum be afterwards and what direction would they be moving.
Solution :
Let, combined velocity of the car is v.
Also, let us assume that mass of both the cars are equal and it is m.
By conservation of momentum :
Initial momentum = Final momentum
m( 6.8 ) - m( 4.4 ) = 2mv
2mv =2.4m
v = 1.2 m/s
Therefore, the velocity of combined car after crash is 1.2 m/s .
Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = 50.4 m/s
Final speed of the ball, v = -37 m/s (As it returns)
(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :

J = -5.24 kg-m/s
(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.


W = -35.1348 Joules
Hence, this is the required solution.
Answer:
25N
Explanation:
formula=> Frictional force= coefficient of friction x normal reaction
normal reaction is mass x gravity(10N/kg)
so Frictional force= 0.5x5x10
=25N
but that is the Frictional force not the constant force
to get the constant force, subtract the Frictional force from the weight of the block
weight= mass x gravity
= 5x10
= 50N
50N-25N
=25N