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pochemuha
2 years ago
12

A solution of carbon dioxide in water has a hydronium ion concentration of 2.0 x 10^−6M. What is the concentration of hydroxide

ion at 25 °C?
Chemistry
1 answer:
kompoz [17]2 years ago
3 0

Answer:

[OH⁻] = 5x10⁻⁹ M

Explanation:

Kw = 1x10⁻¹⁴

[H₃O⁺] . [OH⁻] = Kw

2x10⁻⁶ . [OH⁻] = 1x10⁻¹⁴

[OH⁻] = 1x10⁻¹⁴ / 2x10⁻⁶ → 5x10⁻⁹

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3 years ago
If 1.2 moles of ideal gas occupy a volume of 18.2 L at a pressure of 1.8 ATM what is the temperature of gas in degrees Celsius.
Novosadov [1.4K]

Answer: A 59.5 degree celcius

The equation that we will use to solve this problem is :

PV = nRT where:

P is the pressure of gas = 1.8 atm

V is the volume of gas = 18.2 liters

n is the number of moles of gas = 1.2 moles

R is the gas constant =  0.0821

T is the temperature required (calculated in kelvin)

Using these values to substitute in the equation, we find that:

(1.8)(18.2) = (1.2)(0.0821)(T)

T = 332.5 degree kelvin

The last step is to convert the degree kelvin into degree celcius:

T = 332.5 - 273 = 59.5 degree celcius

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3 years ago
Which of the following organism are most likely to show cospeciation?
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3 years ago
Consider the following reaction: 4Fe + 302 → 2Fe2O3. What mass of iron(III) oxide would
frutty [35]

Answer:

Mass = 357.7 g

Explanation:

Given data:

Mass of Fe =  250 g

Mass of oxygen = 120 g

Mass of iron(III) oxide produced = ?

Solution:

Chemical equation:

4Fe + 3O₂        →     2Fe₂O₃

Number of moles of Fe:

Number of moles = mass/molar mass

Number of moles = 250 g/ 55.8 g/mol

Number of moles = 4.48 mol

Number of moles of O₂ :

Number of moles = mass/molar mass

Number of moles = 120 g/ 32 g/mol

Number of moles = 3.75 mol

Now we will compare the moles of reactants with product.

        Fe          :          Fe₂O₃

        4            :             2

      4.48         :        2/4×4.48 = 2.24

        O₂          :          Fe₂O₃

        3            :             2

      3.75         :        2/3×3.75= 2.5

Less number of moles of Fe₂O₃ are produced by Fe thus it will act as limiting reactant.

Mass of Fe₂O₃:

Mass = number of moles × molar mass

Mass = 2.24 mol × 159.69 g/mol

Mass = 357.7 g

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