Answer:
33 N
Explanation:
v = Velocity of fluid = 8+2 = 10 m/s
= Density of fluid = 1.2 kg/m³
C = Coefficient of drag = 1.1
A = Cross sectional area = 0.5 m²
Drag force is given by
The drag force on the athlete is 33 N
In the absence of air resistance, a ball of mass m is tossed upward to reach a height of 20 m. at the 10 m position, halfway up,
1 answer:
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We can solve the problem by using conservation of energy.
In fact, initially the projectile has only kinetic energy, which is given by
where m is the projectile's mass while
is its initial velocity.
At the point of maximum height, the speed of the projectile is zero, so it only has gravitational potential energy which is equal to
where g is the gravitational acceleration and h is the maximum height of the projectile.
Since the energy must be conserved, we can equalize K and U to find the value of h:
In fact, initially the projectile has only kinetic energy, which is given by
where m is the projectile's mass while
At the point of maximum height, the speed of the projectile is zero, so it only has gravitational potential energy which is equal to
where g is the gravitational acceleration and h is the maximum height of the projectile.
Since the energy must be conserved, we can equalize K and U to find the value of h: