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pickupchik [31]
3 years ago
12

Which of these galaxies would you most likely find at the center of a large cluster of galaxies?

Physics
1 answer:
Arada [10]3 years ago
4 0

Answer:

b. a large elliptical galaxy

Explanation:

In elliptical galaxies the stars are grouped in an elliptical shape, it has a low quantity of gas and dust in comparison to spiral galaxies, and its stars belong to an old population, there is not new stellar formation in it.

The stars orbit in a messy way which made to believe that they form from the merger of galaxies.

They are also really massive (around 10^{4} solar masses).

The most massive and luminous can be found in the center of cluster of galaxies.  

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An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm
Anit [1.1K]

Answer:

The value of d is 20.4 m.

(C) is correct option.

Explanation:

Given that,

Initial velocity = 20 m/s

Final velocity = 0

We need to calculate the time

Using equation of motion

v = u+gt

Where, u = Initial velocity

v = Final velocity

Put the value into the formula

t = \dfrac{20}{9.8}

t= 2.04\ sec

We need to calculate the distance

Using equation of motion

s = ut+\dfrac{1}{2}gt^2

s=0+\dfrac{1}{2}\times9.8\times(2.04)^2

s=20.4\ m

Hence, The value of d is 20.4 m.

4 0
3 years ago
What if is a forecasting game, below are actions on your document and all you have to do is predict what will happen after the a
Talja [164]

1. Triple click on the paragraph.

By extension, the triple click can allow you to select a line and the quadruple click a section (paragraph).

2. Pressing Ctrl + A.

Ctrl+A | Ctrl+E: Select all. Depending on the programs and the translations, it will be one or the other.

3. Double click within the word.

In most text editors, a double-click on a word selects it in its entirety.

4. Pressing key combinations Shift + arrow key.

If you press one of the arrow keys with the Shift key pressed, you can select a section of text.

5. Pressing key combinations Ctrl + End.

Ctrl + End: Go to the end of the document or window.

Ctrl + Home: Go to the beginning of the document or window.

Ctrl + Insert: Copy the selected text.

Please mark me as brainliest.

<h3>➥ I hope I have helped you, greetings! </h3><h3>Atte: ღTheGirlSadღ </h3>
7 0
2 years ago
Read 2 more answers
Engineers are trying to improve a race car. Their goal is to increase the acceleration of the car using the same engine. Which c
Andru [333]

To increase the acceleration of the car using the same engine, the   mass of the car must be decreased.

<h3>What is Newton's first law of motion</h3>

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

The first law is also called the law of inertia because it depends on the mass of the object. The greater the mass, the greater the inertia and more reluctant the object will be to move.

Thus, to increase the acceleration of the car using the same engine, the   mass of the car must be decreased.

a = F/m

Learn more about Newton's law here: brainly.com/question/25545050

#SPJ1

4 0
1 year ago
The universal law of gravitation states that the force of attraction between two objects depends on which quantities?
Ronch [10]

Answer:

D. the masses of the objects and the distance between them

Explanation:

Gravitation is a force, a force doesn't care about the shape or density of objects, only about their masses... and distances.

And you can get it using the following equation:

f = \frac{Gm_{1}m_{2} }{d^{2} }

Where :

G is the universal gravitational constant : G = 6.6726 x 10-11N-m2/kg2

m represent the mass of each of the two objects

d is the distance between the centers of the objects.

4 0
3 years ago
the wattage ratting of a light bulb is the power it sonsumers when it is connected accross a 120 V potential difference what is
igor_vitrenko [27]

Answer:

240 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of current in an electric field. The S.I unit of resistance is ohms (Ω).

The expression for resistance power and voltage is give as,

P = V²/R.......................... Equation 1

Where P = Power, V = Voltage, R = Resistance

Making R the subject of the equation,

R = V²/P.................... Equation 2

Given: V = 120 V, P = 60 W.

Substitute into equation 2

R = 120²/60

R = 240 Ω

Hence the resistance of the bulb = 240 Ω

8 0
3 years ago
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