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3 years ago

1. What do you mean by energy ?

Physics

1 answer:

sammy [17]3 years ago

5 0

Answer:

1. The ability of a body to do a work is called energy.

2. The S.I. unit of energy is joule(J).

3.The different types of energy are :

Mechanical Energy
Heat Energy
Light Energy
Sount Energy
Electrical Energy
Magnetic Energy
Chemical Energy
Nuclear Energy

Explanation:

<h3 /><h3>Hope it works out !!</h3>

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When I hurricane nearest land what causes the most damage

Svetllana [295]

Hey there!

When a hurricane is near land the wind and rain cause the most damage.

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3 years ago

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3 years ago

An astronaut on Earth notes that in her soft drink an ice cube floats with 9/10 of its volume submerged. If she were instead in

riadik2000 [5.3K]

Answer:

B) with 9/10 submerged

Explanation:

$m$ = mass of ice cube

$\rho$ = density of soft drink

$V$ = Volume of soft drink displaced

ice cube floats in the soft drink when the force of buoyancy on it balances its weight. Force of buoyancy acting on the cube in upward direction is same as the weight of the soft drink displaced. hence we can write

weight of ice cube = weight of soft drink displaced

$mg = \rho V g$

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we see that the acceleration due to gravity cancel out both side and hence it does affect as astronaut is on earth on in a lunar module.

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3 years ago

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A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re

fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

Temperature T = 13+273=286 K

Pressure = 10.0 atm

We need to calculate the pressure of the remaining gas

Using equation of ideal gas

$PV=nRT$

For a gas

$P_{1}V_{1}=nRT_{1}$

Where, P = pressure

V = volume

T = temperature

Put the value in the equation

$10\times V=nR\times286$ ....(I)

When the temperature of the gas is increased

Then,

$P_{2}V_{2}=\dfrac{n}{2}RT_{2}$ ....(II)

Divided equation (I) by equation (II)

$\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}$

$\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}$

$P_{2}=\dfrac{10\times368}{2\times286}$

$P_{2}= 6.433\ atm$

$P_{2}=6.4\ atm$

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

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3 years ago

Why must mine tailings be stored and disposed of carefully?

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