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Elan Coil [88]
2 years ago
10

​2(x−8)=x+5x x= −4​ ​x= −16​ ​x= −2​ x = 0

Mathematics
2 answers:
olasank [31]2 years ago
8 0

Answer: X = -4

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.

Margarita [4]2 years ago
6 0
Correct answer: x= -4
Math-way is a great help for questions like these.
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How many solutions does this have? 4x + 12 = -2x + 16
Novay_Z [31]

The equation  4x + 12 = -2x + 16 is one solution.

<h3>What is equation?</h3>

A statement of equality between two expressions consisting of variables and/or numbers.

Given:

4x + 12 = -2x + 16

Now solving for x

4x + 2x = 16 - 12

6x = 4

x= 4/6

x=2/3

Hence, the equation  4x + 12 = -2x + 16 has one solution.

Learn more about equation here:

brainly.com/question/16255566

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6 0
1 year ago
What is (+,+) reflected over the x axis?
sleet_krkn [62]

Answer:

means the the x-axis is positive and the y-axis is positive so it is located in the first quarter of the cariesian corrdenates

5 0
3 years ago
Read 2 more answers
Which are the solutions of x2 = –5x + 8? SOLUTIONs ok not a single answer i need to know its opposite
AlekseyPX

Answer:

I think it is -5+root-7/2 & -5-root-7/2

Step-by-step explanation:


5 0
4 years ago
Are the two triangles below similar?
Luda [366]

Answer :- Yes the two triangles are similar because there are two pairs of congruent corresponding angles.

Explanation:-

In Δ ABC

∠A=30° , ∠C=65 °

By angle sum property of triangle

∠A + ∠B + ∠C= 180°

⇒∠B= 180°-∠A-∠C=180°-30°-65°=85°

⇒∠B=85°

Now in ΔABC and ΔDEF

∠A=∠D=30° and ∠B=∠E=85°

⇒ there are two pairs of congruent corresponding angles.

So by AA-similarity criteria

ΔABC ≈ ΔDEF




3 0
3 years ago
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AREA ADDITION AND SUBTRACTION ASSISTANCE?
Tom [10]

The shaded area is a segment. The area of a segment is

A_{segment}=A_{sector}-A_{triangle}.

You know radius that is the side of isosceles triangle and measure of angle between two equal triangle sides, then

A_{triangle} =\dfrac{1}{2} a\cdot a \sin \alpha=\dfrac{1}{2} 18.6\cdot 18.6 \cdot  \sin 123^{\circ}=172.98\cdot  \sin 123^{\circ}=145.07 sq. m..

The area of sector is A_{sector}=\dfrac{r^2\cdot \alpha}{2}= \dfrac{(18.6)^2\cdot 0.68\pi}{2}=117.63\pi=369.53 sq. m..

Then A_{segment}=369.53-145.07=224.46 sq. m.

Answer: A_{segment}=224.46 sq. m.

7 0
3 years ago
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