Each of the chemically active Period 2 elements forms stable compounds in which it has bonds to fluorine.(a) What are the names
1 answer:
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<u>Answer:</u> The formula of the compound formed between rubidium and fluorine is RbF
<u>Explanation:</u>
Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.
The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.
Rubidium is the 37th element of the periodic table having electronic configuration of
This will loose 1 electron to form ion
Fluoride is the 9th element of the periodic table having electronic configuration of
This will gain 1 electron to form ion
To form compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion
The formation of the given compounds is shown in the image below.
Answer: 1.47
Explanation:
The combined gas equation when pressure is constant:
where,
=original number of moles of air in the balloon = ?
= number of moles of air in the heated balloon = ?
= initial volume of gas =
= final volume of gas =
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get the final pressure of gas.
Therefore, the ratio of the number of moles of air in the heated balloon to the original number of moles of air in the balloon is 1.47