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ss7ja [257]
3 years ago
5

If you were converting from milli- to centi- units, would you move the decimal point to the left or the right

Chemistry
1 answer:
yan [13]3 years ago
6 0

Answer:

Left

Explanation:

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a solution of HCI contains 36 percent HCI,by mass and calculate the mole fraction of HCI in the solution?​
denis-greek [22]

Explanation:

You have a solution that contains 36 g HCl dissolved in 64 g water

Molar mass HCl = 36.45 g/mol

Mol HCl in 36 g = 36 g / 36.45 g/mol = 0.9876 mol

Molar mass H2O = 18 g/mol

Mol H2O in 64 g = 64 g / 18 g/mol = 3.5556 mol

Total mol = 0.9875 + 3.5556 = 4.5431 mol

Mol fraction HCl = 0.9876 mol / 4.5431 mol = 0.2174

Mol fraction H2O = 3.5556 / 4.5431 = 0.7826

The answer should have 2 significant digits:

Mol fraction HCl = 0.22

Mol fraction H2O = 0.78

Mol fraction has no units.

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4 0
2 years ago
When comparing the two elements P and I , the element with the higher first ionization energy is PP When comparing the two eleme
Anni [7]

Answer:

Explanation:

The first ionization energy varies in a predictable way across the periodic table. The ionization energy decreases from top to bottom in groups, and increases from left to right across a period. Thus, helium has the largest first ionization energy, while francium has one of the lowest.

6 0
3 years ago
How did Bohr refine the model of the atom? How did Bohr refine the model of the atom? He developed electrochemistry. He discover
BartSMP [9]

Answer:

He developed the concept of concentric electron energy levels

Explanation:

Before Bohr's model, Rutherford's model was proposed. This model explains most of the properties of the atom but failed to explain the stability of the atom.

As per Rutherford's model, electrons revolve around the nucleus in the orbit.

But revolving electron in their orbit around nucleus would give up energy and so gradually move towards the nucleus and therefore, eventually collapse.

Bohr's proposed that the electrons around the nucleus move orbit of fixed energy called "stationary states". Electrons in these stationary states  do not radiate energy.

Therefore, proposal of concentric electron energy levels refine the atomic models.

5 0
3 years ago
Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6
liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 137ml+137ml=274ml

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 274 g

T_{final} = final temperature of water = 325.8 K

T_{initial} = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

q=274g\times 4.18J/g^oC\times (325.8-298)K

q=31839.896J=31.84KJ

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0
3 years ago
An adult mosquitoes lifespan is about 16 days how many minutes is that
Delicious77 [7]
1 day = 1, 440 minutes
16 days = (1, 440 × 16) days = 23, 040 minutes
5 0
3 years ago
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