Ribosomes
Cytoplasm
Mitochondria
Nucleus
Cell wall and chloroplasts
Lysosome
Golgi apparatus
Endoplasmic reticulum
During meiosis when the spindle fibers pull apart the chromosomes this happens at radon so there are different variations of genes being pulled apart
Answer: genotypic ratio 2/4
Phenotypic ratio 4/4 is the same
Explanation: suppose RR is the dominant female and Rr is the heterozygous male. Then after the cross genetically 2 have RR and 2 have Rr ratio. But phenotypically all 4 are the same.
Answer:
They difference in phenotypes is dependent on the genes. The more dominant gene will overpower a recessive gene, or if there are two recessive genes together, that will be the phenotype. When things are cross breaded they introduce different genotypes that allow for different looking phenotypes.
Example: Dominant blue flower (Bb) mixed with recessive yellow flower (bb)
B b
b Bb bb
b Bb bb
There is a 50/50 chance the offspring will be either blue or yellow
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
