<u>Answer:</u> The volume of stock solution of strontium hydroxide needed is 4.125 mL
<u>Explanation:</u>
1 mole of produces 1 mole of strontium ions and 2 moles of hydroxide ions
Molarity of diluted strontium hydroxide solution =
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated strontium hydroxide solution
are the molarity and volume of diluted strontium hydroxide solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution of strontium hydroxide needed is 4.125 mL
Answer:
2 C6H6 + 15 O2 ( 12 CO2 + 6 H2O
Explanation:
The answer is: 1.5 moles of oxygen are present.
V(O₂) = 33.6 L; volume of oxygen.
p(O₂) = 1.0 atm; pressure of oxygen.
T = 0°C; temperature.
Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).
At STP one mole of gas occupies 22.4 liters of volume.
n(O₂) = V(O₂) ÷ Vm.
n(O₂) = 33.6 L ÷ 22.4 L/mol.
n(O₂) = 1.50 mol; amount of oxygen.
Mixing equal amounts of a strong acid with a strong base also produces a neutral pH (pH = 7) solution<span>.
</span>A neutralization reaction<span> is when an acid and a base</span>react<span> to form water and a salt and involves the combination of H</span>+<span> ions and OH</span>-<span> ions to generate water. The </span>neutralization<span> of a strong acid and strong base has a pH equal to 7.</span>