Given: M = 0.0150 mol/L HF solution T = 26°C = 299.15 K π = 0.449 atm
Required: percent ionization
Solution: First, we get the van't Hoff factor using this equation: π = i MRT 0.449 atm = i (0.0150 mol/L) (0.08206 L atm / mol K) (299.15 K) i = 1.219367
Next, calculate the concentration of the ions and the acid. We let x = [H+] = [F-] [HF] = 0.0150 - x
Adding all the concentration and equating to iM x +x + 0.0150 - x = <span>1.219367 (0.0150) x = 3.2905 x 10^-3
Answer: The body produce NADPH a reducing equivalents as antioxidants.
Explanation:
During the pentose phosphate pathway reducing equivalents like NADPH is produced which help to prevent oxidative stress. It reduces glutathione via glutathione reductase which converts reactive H2O2 to H2O by glutathione peroxidase.