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frutty [35]
3 years ago
5

A group of students used the instructions below to make a model of a watershed. When water washes over the water-soluble ink, th

e water will change color. Movement of water on the model can help identifyó A. groundwater pollution B. nonpoint source pollution C. changes in watershed size D. evaporation in the water cycle
Chemistry
1 answer:
shusha [124]3 years ago
8 0

Answer: A

Explanation: ground water pollution.

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Jerry listed the following process on his notebook:
topjm [15]

Answer:

2

Explanation:

1. The dew is formed when the water vapor at the atmosphere contacts the leaves, which are at a low temperature, so, the vapor temperature decreases, and the liquid is formed. So, it's a gas to liquid change.

2. Ice cubes are at the solid-state, thus this transformation is solid to a liquid change.

3. The cold juice is at a low temperature, so when the water vapor of the air contacts with the glass, its temperature decreases, and its change to a liquid phase. So, it's a gas to liquid change.

4. The evaporated water from the Earth's surface goes to the atmosphere, and, at high altitudes, the temperature is low, so the water vapor condenses and the drops get closer together forming the clouds. So, it's a gas to a liquid change.

5 0
3 years ago
How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas
IrinaVladis [17]

94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

where

<em>m</em> represents the mass and

<em>C</em> represents the percent concentrations

We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %

<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %

∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

4 0
3 years ago
How is mercury obtained and separated from other nearby substances?​
VLD [36.1K]

Answer:

Most mercury forms in a sulfide ore called cinnabar, but mercury is also frequently found in small amounts in other ores. A common method for separating mercury from cinnabar is to crush the ore and then heat it in a furnace in order to vaporize the mercury. This vapor is then condensed into liquid mercury form.

Explanation:

7 0
2 years ago
Read 2 more answers
put the following in order from LARGEST TO SMALLEST nuclueus,molecule,electron,atom,proton and a teacher
SVETLANKA909090 [29]

Answer:

electron, proton, nucleus, atom, molecule teacher

3 0
3 years ago
Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
5 0
3 years ago
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