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olga55 [171]
1 year ago
9

Which one of the following set of quantum numbers repesents the electron with the highest energy?

Chemistry
1 answer:
Andre45 [30]1 year ago
3 0

The set of quantum numbers represents the electron with the highest energy is option C which is

(n=4,l=2,m=1,s=+1/2) represents the highest energy of an atom.

<h3>What is quantum number?</h3>

Quantum numbers refer to numbers or values that exist in quantunized elements which is use to describe the level of flow of energy that exist between the atoms or molecules of such elements. It is use to describe the position of atoms.

Therefore, The set of quantum numbers represents the electron with the highest energy is option C which is

(n=4,l=2,m=1,s=+1/2) represents the highest energy of an atom.

The question is incomplete, below us the completed part gotten from another website.

A n= 3, l = 1, m = 1, s = +½

(B) n = 3, l = 2, m = 1, s = +½

(C) n = 4, l = 0, m = 0, s = +½

(D) n = 3, l = 0, m = 0, s = +½

Learn more about quantum numbers below.

brainly.com/question/2292596

#SPJ1

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Why do we use the term formula unit for ionic compounds instead of the term molecule? Select all that apply.
VladimirAG [237]

Answer:

A and C

Explanation:

The term formula unit is use to indicate Simple-Whole Ratios of ions in a compound. KEY WORD! RATIO!

3 0
2 years ago
Paliwanag ang kahalagahan ng papa at ng holy roman emperor sa panahong midieval.
Doss [256]

Explanation:

The Holy Roman Empire (Latin: Sacrum Imperium Romanum; German: Heiliges Römisches Reich), also termed as the First Reich, was a multi-ethnic complex of territories in Western and Central Europe that developed during the Early Middle Ages and continued until its dissolution in 1806 during the Napoleonic Wars.[6] The largest territory of the empire after 962 was the Kingdom of Germany, though it also included the neighboring Kingdom of Bohemia and Kingdom of Italy, plus numerous other territories, and soon after the Kingdom of Burgundy was added. However, while by the end of the 15th century the Empire was still in theory composed of three major blocks – Italy, Germany, and Burgundy – in practice only the Kingdom of Germany remained, with the Burgundian territories lost to France and the Italian territories, ignored in the Imperial Reform, although formally part of the Empire, were splintered into numerous de facto independent territorial entities.[7][8][9][10] The external borders of the Empire did not change noticeably from the Peace of Westphalia – which acknowledged the exclusion of Switzerland and the Northern Netherlands, and the French protectorate over Alsace – to the dissolution of the Empire. By then, it largely contained only German-speaking territories, plus the Kingdom of Bohemia, the southern Netherlands and lands of Carniola. At the conclusion of the Napoleonic Wars in 1815, most of the Holy Roman Empire was included in the German Confederation.

in yr language:

Ang Holy Roman Empire (Latin: Sacrum Imperium Romanum; German: Heiliges Römisches Reich), na tinawag din bilang First Reich, ay isang multi-etniko na kumplikado ng mga teritoryo sa Kanluran at Gitnang Europa na d

3 0
3 years ago
Suppose a 1.0 L solution contains 0.020 M in Cu(NO3)2, then 0.40 moles of NH3 are added. Assuming no change in volume, what is t
Rasek [7]

Answer:

4.6*10^{-14} M

Explanation:

Concentration of Cu^{2+} = [Cu(NO_3)_2] = 0.020 M

Constructing an ICE table;we have:

                                 Cu^{2+}+4NH_3_{aq} \rightleftharpoons [Cu(NH_3)_4]^{2+}_{(aq)}

Initial (M)             0.020          0.40                        0

Change (M)         -  x                - 4 x                       x

Equilibrium (M)  0.020 -x        0.40 - 4 x              x

Given that: K_f =1.7*10^{13}

K_f } = \frac{[Cu(NH_3)_4]^{2+}}{[Cu^{2+}][NH_3]^4}

1.7*10^{13} = \frac{x}{(0.020-x)(0.40-4x)^4}

Since x is so small; 0.40 -4x = 0.40

Then:

1.7*10^{13} = \frac{x}{(0.020-x)(0.0256)}

1.7*10^{13} = \frac{x}{(5.12*10^{-4}-0.0256x)}

1.7*10^{13}(5.12*10^{-4} - 0.0256x) = x

8.704*10^9-4.352*10^{11}x =x

8.704*10^9 = 4.352*10^{11}x

x = \frac{8.704*10^9}{4.352*10^{11}}

x = 0.0199999999999540

Cu^{2+}= 0.020 - 0.019999999999954

Cu^{2+} = 4.6*10^{-14} M

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Answer:

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