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umka2103 [35]
3 years ago
13

What volume (in liters) does 2.895 moles of oxygen occupy at stp?

Chemistry
1 answer:
LekaFEV [45]3 years ago
5 0

Answer:

64.9 L

Explanation:

pls mark as brainliest

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What is the wavelength of radio waves? Which statement is true for a cooling curve? A. It shows how the temperature of the subst
ladessa [460]

Answer:

Most radio waves have wavelengths between 1 mm and 100 km.

A cooling curve shows A. how the temperature of a substance falls as heat is removed.

Explanation:

<em>Radio waves</em> are the longest of all the waves in the electromagnetic spectrum.

Most have wavelengths between 1 mm and 100 km, although there is no upper limit.

Some radio waves have wavelengths of 10 000 km.

A <em>cooling curve</em> (see image below) shows how the temperature of a substance falls as it is cooled.

In Option E., a decrease in temperature would cause an energy <em>loss</em>.

Options B., C., and D. involve the <em>addition of heat</em>.

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4 years ago
In a soil profile, which is the second layer?<br> solid rock<br> subsoil<br> parent rock<br> topsoil
taurus [48]

Subsoil is the layer of soil under the topsoil on the surface of the ground.

7 0
3 years ago
What do you know about Relative Dating
gizmo_the_mogwai [7]
<span>it tells you the sequence in which events occurred, not how long ago they occurred.</span>
8 0
3 years ago
Use bond energies to calculate the enthalpy of reaction for the combustion of ethane. Average bond energies in kJ/mol C-C 347, C
ivanzaharov [21]

The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.

The reaction is:

2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O  (1)  

The enthalpy of reaction (1) is given by:

\Delta H = \Delta H_{r} - \Delta H_{p}   (2)

Where:

r: is for reactants

p: is for products

The bonds of the compounds of reaction (1) are:

  • 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
  • 7O₂: 7 moles of 1 O=O bond  
  • 4CO₂: 4 moles of 2 C=O bonds  
  • 6H₂O: 6 moles of 2 H-O bonds

Hence, the enthalpy of reaction (1) is (eq 2):

\Delta H = \Delta H_{r} - \Delta H_{p}

\Delta H = 2*\Delta H_{CH_{3}CH_{3}} + 7\Delta H_{O_{2}} - (4*\Delta H_{CO_{2}} + 6*\Delta H_{H_{2}O})      

\Delta H = 2*(6*\Delta H_{C-H} + \Delta H_{C-C}) + 7\Delta H_{O=O} - (4*2*\Delta H_{C=O} + 6*2*\Delta H_{H-O})  

\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol  

\Delta H = -2860 kJ/mol          

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.

Read more here:

brainly.com/question/11753370?referrer=searchResults  

I hope it helps you!        

7 0
3 years ago
Why is it impossible to ever prove that a hypothesis is true?
maria [59]

Answer: A

Explanation:

Hypothesis have to be based on previous knowledge and have to be able to be tested but the problem is most hypothesis can’t be explained so it’s impossible to prove a hypothesis correct because science uses inductive reasoning

4 0
3 years ago
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