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Lunna [17]
3 years ago
7

Which of the following accurately describes carbon atoms?

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
3 0
I think that it's A.

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Alkanes are hydrocarbons that contain what type of bonds
olga2289 [7]
Carbon carbon triple bonds
3 0
2 years ago
Read 2 more answers
How is the law of conservation of matter represented in a chemical reaction?
blondinia [14]

Answer:

By balancing the chemical equation  

Explanation:

The Law of Conservation of Matter states that matter cannot be destroyed nor created.

That is, you must have the same amount of matter before and after a reaction.

Atoms are made of matter, so you must have the same number of each type of atom in the reactants as in the products. You must balance the equation.

Consider the reaction

2H₂ + O₂ ⟶ 2H₂O

You must have 2s in front of H₂ and H₂O to balance the atoms.

They give you four atoms of H and two atoms of O on each side of the arrow.

5 0
3 years ago
Be sure to answer all parts. For the complete redox reactions given here, write the half-reactions and identify the oxidizing an
OlgaM077 [116]

Answer : O_2 is the oxidizing agent and Fe is the reducing agent.

Explanation :

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

4Fe+3O_2\rightarrow 2Fe_2O_3

The half oxidation-reduction reactions are:

Oxidation reaction : Fe\rightarrow Fe^{3+}+3e^-

Reduction reaction : O_2+4e^-\rightarrow 2O^{2-}

In order to balance the electrons, we multiply the oxidation reaction by 4 and reduction reaction by 3 then added both equation, we get the balanced redox reaction.

Oxidation reaction : 4Fe\rightarrow 4Fe^{3+}+12e^-

Reduction reaction : 3O_2+12e^-\rightarrow 6O^{2-}

4Fe+3O_2\rightarrow 2Fe_2O_3

In this reaction, 'Fe' is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and 'O_2' is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, O_2 is the oxidizing agent and Fe is the reducing agent.

7 0
3 years ago
Identify the following example as a physical or chemical change. Moisture in the air forms beads of water on a cold window pane.
denis23 [38]

<u>Answer:</u> The given example is a physical change.

<u>Explanation:</u>

A chemical change is defined as the change in which chemical composition of a substance changes and results in the formation of a new substance. These are usually irreversible process.

A physical change is defined as the change in which only the shape and size of the substance changes and no new substance is formed. Only phase change occurs in these processes. These are usually considered as a reversible change.

For the given example: Moisture in the air forms beads of water on a cold window pane.

This is a physical change because water was initially present in the gaseous state (Moisture in the air) and when it is coming in contact with the cold window pane, the gaseous state of water gets converted into a liquid state.

Hence, the given example is a physical change.

6 0
2 years ago
A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera
Grace [21]

Answer: The initial temperature of the iron was 515^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of iron = 360 g

m_2 = mass of water = 750 g

T_{final} = final temperature = 46.7^0C

T_1 = temperature of iron = ?

T_2 = temperature of water = 22.5^oC

c_1 = specific heat of iron = 0.450J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]

T_i=515^0C

Therefore, the initial temperature of the iron was 515^0C

4 0
2 years ago
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