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2 years ago

A hailstone, 120 m above the

Physics

1 answer:

Stells [14]2 years ago

4 0

The hailstone will hit the earth in 4.04 seconds.

we move 9.8 meters per second faster thanks to gravity. we start to fall after one second at 9.8 m/s. we start falling at 19.6 m/s after two seconds, and so forth.

From the query, the following information may be deduced:

Height (H) = 120 m

Gravitational acceleration (g)=9.8 m/s2.

Time (t)=?

It is possible to determine the hailstone's impact time as:

h=1/2 gt²

120= 1/2 x 9.8 x t²

120x2/9.8=t²

t²=24.48

t=4.94 s

therefore, the calculated time taken is 4.94 s.

Learn more about gravity here-

brainly.com/question/14155948

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What is the frequency of a wave if 10 waves go past in 1 second ?

KIM [24]

Answer:

f = 10 Hz

Explanation:

We need to find the frequency of a wave if 10 waves go past in 1 second. Total number of waves per unit time is called frequency. So,

$f=\dfrac{10}{1}=10\ Hz$

So, the frequency of a wave is 10 Hz.

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3 years ago

Which characteristics belong to Whittaker’s classification system? Select two options.

Lana71 [14]

Answer:

Five kingdoms & Seven levels

Explanation:

Robert H. Whittaker proposed five kingdom classical system for living organisms in 1969. These were: Kingdom Monera, Kingdom Protista, Kingdom Fungi, Kingdom Animalia, and Kingdom Plantae. His work was the improvement of earlier work conducted by Carl Linnaeus who proposed three kingdom classification system (Animalia, Plantae, and Protista).

Whittaker's system further categorized each kingdom to seven levels. These were: Kingdom → Phylum → Class → Order → Family → Genus → Species. This categorization was based on similarities in organisms at different levels.

PS: The scientific name of each organism is the combination of genus and family name.

4 0

3 years ago

Read 2 more answers

Which of the following can be computed?

Musya8 [376]

Answer: only the third option. [Vector A] dot [vector B + vector C]

The dot between the vectors mean that the operation to perform is the "scalar product", alson known as "dot product".

This operation is only defined between two vectors, not one scalar and one vector.

When you perform, in the first option, the dot product of any ot the first and the second vectors you get a scalar, then you cannot make the dot product of this result with the third vector.

For the second option, when you perform the dot product of vectar B with vector C you get a scalar, then you cannot make the dot product ot this result with the vector A.

The third option indicates that you sum the vectors B and C, whose result is a vector and later you make the dot product of this resulting vector with the vector A. Operation valid.

The fourth option indicates the dot product of a scalar with the vector A, which we already explained that is not defined.

5 0

3 years ago

A rocket is launched upward with a constant acceleration of 165 m/s^2. After 8.00 seconds of ascension a passenger on the rocket

Novay_Z [31]

To solve this problem we will apply the concepts related to the linear kinematic movement. We will start by finding the speed of the body from time and the acceleration given.

Through the position equations we will calculate the distance traveled.

Finally, using this same position relationship and considering the previously found speed, we can determine the time to reach your goal.

For time (t) and acceleration (a) we have to,

$t = 8s, a = 165m/s^2$

The velocity would be,

$u = a*t \\u = 165*8\\u = 1320m/s$

Now the position is,

$h= \frac{1}{2} at^2$

$h = \frac{1}{2} 165*8^2$

$h = 5280m$

Now with the initial speed and position found we will have the time is,

$h=ut +\frac{1}{2} at^2$

$-5280=1320t - \frac{1}{2} 9.8t^2$

$4.9t^2-1320t-5280=0$

Solving the polynomian we have,

$t = 273.33s = 4.56minutes$

Therefore the rocket will take to hit the ground around to 4.56min

5 0

3 years ago

Three people are pushing a 500 kg of box in the same direction. applied forces are 30 n, 20 n, and 10 n respectively. if the acc

GREYUIT [131]

The total force applied by the three people is:
$F=30 N+20 N+10 N=60 N$
This force is pushing toward the direction of the motion, while the frictional force $F_f$ points in the opposite direction.
We can write Newton's second law applied to the block: the resultant of the two forces must be equal to the product between the block's mass and its acceleration
$F-F_f = ma$
We know the mass of the block, m=500 kg, and the acceleration, $a=0.02 m/s^2$ , so we can find the friction:
$F_f = F-ma=60 N - (500 kg)(0.02 m/s^2)=50 N$

8 0

4 years ago