Answer:
250 J
Explanation:
Apply the formula:
K = 1/2.m.v²
K = 1/2.5.10²
K = 1/2.5.100
K = 5.50
K = 250 Joules
But, remember that if the speed is accelerating or not, if it is, then we need to know the point in time that the question is asking for the Kinetic Energy.
In this case, I think it is just a constant speed.
Answer:
F = 37.8 × 10^(6) N
Explanation:
The charges are 0.06 C and 0.07 C.
Thus;
Charge 1; q1 = 0.06 C
Charge 2; q2 = 0.07 C
Distance between them; r = 3 m
Formula for the force in between them is;
F = kq1•q2/r²
Where k is a constant = 9 × 10^(9) N.m²/C²
Thus;
F = (9 × 10^(9) × 0.06 × 0.07)/3²
F = 37.8 × 10^(6) N
Answer:
39.6 m/s
Explanation:
Taking down to be positive:
Given:
v₀ = 0 m/s
a = 9.8 m/s²
Δy = 80 m
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (9.8 m/s²) (80 m)
v = 39.6 m/s
Answer:
346 * 10⁶ m
Explanation:
The force of gravity of the earth that will cancel the the force of gravity exerted by the moon will be equal to each other
Let 
be the force of gravity exerted by the earth
and let 
be the force of gravity exerted by the moon
According to Newton's law of universal gravitation, the force of attraction between two different masses, m₁ and m₂ separated by a distance, d, is given by:
Mass of the earth, 
Mass of the moon, 
Mass of the satellite, 
...............................(1)
The earth and the moon are separated by a distance, 3.844 * 10⁸ m
............................(2)
Equating equations (1) and (2)
Factorising out 
Solving for d in the quadratic equation above:
d = 346 * 10⁶ m
Answer:
42.58kg
Explanation:
By Newton's second law, F = ma.
F is the force being applied, in this case 112N. a is the acceleration, in this case 2.63 m/s^2.
Thus, with some simple algebraic manipulation, we get the mass to equal:
m = F/a = 112N / 2.63 m/s^2 = 42.58kg
