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Art [367]
3 years ago
6

On a good night, the front row of the Twisted Sister concert would surely result in a 120 dB sound level. An IPod produces 100 d

B. How many IPods would be needed to produce the same intensity as the front row of the Twisted Sister concert?
Physics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

100 iPods

Explanation:

The deciBell scale is logarithmic, and thus, it turns multiplying into adding.

Initially, it was the Bell scale, purely logarithmic, where "times 10" is translated into "plus 1" (just like normal logs). However, the steps became too big and so they divided the Bell in 10 parts, the deciBell.

The levels above could well have been called 10B and 12B.

Usually, we define the dB scale for intensity as:

I(dB) = 10•log(I)

Thus,

I = 10^(I(dB)/10)

Now 120 dB gives us units of I = 10^(120/10) = 10^12 Pa (assume the dB are measured to 1 Pa) and 100 dB is 10^10 Pa.

Thus, we would need 100 ipods to get the same intensity

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What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 29.5 km/h and the μs
Yakvenalex [24]

Answer:

Radius=15.773 m

Explanation:

Given data

v=29.5 km/h=8.2 m/s

μs=0.435

To find

Radius R

Solution

The acceleration is a centripetal acceleration  which is experienced by the bicycle given by

a=v^{2}/R

This acceleration is only due to static force which given as

f=ma\\f=m(v^{2}/R )

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Fs_{max}=u_{s}F_{N}

where

FN is normal force equal to mass*gravity

Therefore when the car is on the verge of sliding

f=fs_{max}\\ m(v^{2}/R )=u_{s}mg

Therefore the minimum radius should be found by the bicycle move without  sliding

So

v^{2}/R=u_{s}g\\  R=v^{2}/u_{s}g\\R=(8.2)^{2}/(0.435*9.8)\\R=15.773m

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3 years ago
How many moles of He atoms are in 6.00 g of He?
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4 0
3 years ago
in a solar system far, far away the sun's intensity is 200 w/m2 for an inner planet located a distance r away. what is the sun's
GarryVolchara [31]

The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.

<h3>What is the Inverse Square Law formula?</h3>

The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}

Where

  • I₁ = Intensity at distance 1 (W/m²)
  • I₂ = Intensity at distance 2 (W/m²)
  • d₁ = distance 1 from a light source (m)
  • d₂ = distance 2 from a light source (m)

Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?

By using the inverse square law formula, the sun's intensity for an outer planet is

\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}

\frac{200 }{I_{2} } = \frac{(6r)^{2} }{r^{2}}

\frac{200 }{I_{2} } = \frac{36r^{2} }{r^{2}}

I_{2} = \frac{200} {36}

I₂ = 5.55 W/m²

Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².

Learn more about intensity of light here:

brainly.com/question/13155277

#SPJ4

3 0
1 year ago
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