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2 years ago

The mass of an atom of carbon-12 (Z = 6) is less than the mass of 6 protons and 6 neutrons because of

Physics

1 answer:

Orlov [11]2 years ago

4 0

Because 2 carbon attach to one's of each of the others

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A piano string having a mass per unit length equal to 4.70 10-3 kg/m is under a tension of 1 400 N. Find the speed with which a

sweet [91]

Answer:

The speed of the sound wave on the string is 545.78 m/s.

Explanation:

Given;

mass per unit length of the string, μ = 4.7 x 10⁻³ kg/m

tension of the string, T = 1400 N

The speed of the sound wave on the string is given by;

$v = \sqrt{\frac{T}{\mu} }$

where;

v is the speed of the sound wave on the string

Substitute the given values and solve for speed,v,

$v = \sqrt{\frac{T}{\mu} }\\\\v = \sqrt{\frac{1400}{4.7*10^{-3}} }\\\\v = \sqrt{297872.34}\\\\v = 545.78 \ m/s$

Therefore, the speed of the sound wave on the string is 545.78 m/s.

3 0

2 years ago

A 1.1-kg uniform bar of metal is 0.40 m long and has a diameter of 2.0 cm. When someone bangs one end of this bar, a 1.5 MHz sho

lyudmila [28]

Answer:

$\lambda = 2.22\times 10^{-3}\ m$

Explanation:

Given,

mass of the bar = 1.1 Kg

length of rod, l = 0.40 m

diameter of the rod, d = 2 cm

frequency, f = 1.5 MHz

time, t = 0.12 ms

wavelength of the shock wave = ?

Speed of the wave = $\dfrac{L}{t}=\dfrac{0.40}{0.12\times 10^{-3}}$

v = 3333.33 m/s

wavelength of the wave

$\lambda = \dfrac{v}{f}= \dfrac{3333.33}{1.5\times 10^6}$

$\lambda = 2.22\times 10^{-3}\ m$

6 0

2 years ago

Question below...............

kondaur [170]

Answer:

friction force

Explanation:

force of friction is opposite to the force applied it resist the motion

7 0

2 years ago

A jetliner, traveling northward, is landing with a speed of 71.9 m/s. Once the jet touches down, it has 675 m of runway in which

Leviafan [203]

Answer:

The value is $a = -3.7 \ m/s^2$

Explanation:

From the question we are told that

The landing speed is $u = 71.9 \ m/s$

The distance traveled is $d = 675 \ m$

The velocity it is reduced to is $v = 11.3 \ m/s$

Generally the average acceleration is mathematically represented as

$a = \frac{ v^2 - u^2 }{ 2 * d }$

=> $a = \frac{ 11.3^2 - 71.9^2 }{ 2 * 675 }$

=> $a = -3.7 \ m/s^2$

5 0

2 years ago

A 2.0m long pendulum is released from rest when the support string is at an angle of 25 degrees with the vertical. What is the s

Blizzard [7]

Answer:

$v=1.92m/s$

Explanation:

Given data

Length h=2.0m

Angle α=25°

To find

Speed of bob

Solution

From conservation of energy we know that:

$P.E=K.E\\mgh=(1/2)mv^{2}\\ gh=(1/2)v^{2}\\v^{2}=\frac{gh}{0.5}\\ v=\sqrt{\frac{gh}{0.5}}\\ v=\sqrt{\frac{(9.8m/s^{2} )(2.0-2.0Cos(25^{o} ))}{0.5}}\\v=1.92m/s$

8 0

2 years ago