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Sidana [21]
4 years ago
14

How do you know if a boy like you?

Physics
1 answer:
adell [148]4 years ago
6 0

Answer:

They cherish you

Explanation:

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What is the displacement of the student from the bus stop to the mailbox?
Reika [66]

Answer:C

Explanation:

5 0
3 years ago
In an isolated system, a red ball of mass m moves to the right with speed v. It strikes a green ball, of
ella [17]
The answer is D. To the left with speed 2v
4 0
3 years ago
Paco was driving his scooter west with an initial velocity of 4 m/s. he accelerates at 0.5 m/s2 for 30 seconds. what is his fina
sleet_krkn [62]

The final velocity will be 19 m/sec.Option C is correct.

<h3>What is velocity?</h3>

The change of displacement with respect to time is defined as the velocity.  

Velocity is a vector quantity. it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.

From Newton's first equation of motion;

\rm v = u+at \\\\ v= 4+ 0.5 \times 30 \\\\ v= 19 \ m/sec

The final velocity will be 19 m/sec

Hence, option C is correct.

To learn more about the velocity refer to the link ;

brainly.com/question/862972

#SPJ1

4 0
2 years ago
A basketball player jumps 76cm to get a rebound. How much time does he spend in the top 15cm of the jump (ascent and descent)?
vesna_86 [32]

Answer:

The time for final 15 cm of the jump equals 0.1423 seconds.

Explanation:

The initial velocity required by the basketball player to be able to jump 76 cm can be found using the third equation of kinematics as

v^2=u^2+2as

where

'v' is the final velocity of the player

'u' is the initial velocity of the player

'a' is acceleration due to gravity

's' is the height the player jumps

Since the final velocity at the maximum height should be 0 thus applying the values in the above equation we get

0^2=u^2-2\times 9.81\times 0.76\\\\\therefore u=\sqrt{2\times 9.81\times 0.76}=3.86m/s

Now the veocity of the palyer after he cover'sthe initial 61 cm of his journey can be similarly found as

v^{2}=3.86^2-2\times 9.81\times 0.66\\\\\therefore v=\sqrt{3.86^2-2\times 9.81\times 0.66}=1.3966m/s

Thus the time for the final 15 cm of the jump can be found by the first equation of kinematics as

v=u+at

where symbols have the usual meaning

Applying the given values we get

t=\frac{v-u}{g}\\\\t=\frac{0-1.3966}{-9.81}=0.1423seconds

4 0
3 years ago
Answer the question please
kirill [66]

Answer:

i think is third

Explanation:

7 0
4 years ago
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